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s2008m [1.1K]
2 years ago
8

Please help me find the same denominator

Mathematics
2 answers:
serious [3.7K]2 years ago
8 0

Answer:

Step-by-step explanation:

you have to multiply first fraction with '8' and second fraction with '10' :

the fractions will become 72/80 and 70/80 then you can compare it

Lelechka [254]2 years ago
6 0

Answer:

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

let us first start with some basic information ~

A fraction can be represented as \frac{x}{y}\\ where ,

x is the numerator and y is the denominator !

the question asks us to do something that will help us get same denominator for both the terms !

so let's see what we should do in such a case ~

\frac{9}{10}  \: and \:  \frac{7}{8}  \\ \\ \\ lets \: make \: the \: denominator \: of \: both \\ the \: terms \: reach \: 80 \: , \\  \\ \bold\orange{ \implies \: \frac{9}{10}  \times  \frac{8}{8}  = }\bold\red{ \frac{72}{80}}  \\  \\\bold\orange{ \implies \:  \frac{7}{8}  \times  \frac{10}{10}  =}\bold\red{  \frac{70}{80}}

and we're done !

let's add some more info to be lil more clear ~

while converting the denominator of both the terms , we must multiply the same number ( this number refers to the one we'll have to multiply to the denominator to obtain the desired result ) with the denominator as well as with the numerator !

hope helpful :D

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Solve for x PLS HELP NOW
Zepler [3.9K]

Answer:

x=70

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

<u />\frac{0.35}{\frac{2}{3}x } =\frac{0.45}{x-10}<u />

<u />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Cross-multiply:                    0.35(x-10)=\frac{2}{3} x \cdot 0.45
  2. Distribute 0.35:                   0.35x - 3.5=\frac{2}{3} x \cdot 0.45
  3. Multiply:                               0.35x - 3.5=0.3x
  4. Isolate <em>x</em> term:                     -3.5=-0.05x
  5. Isolate <em>x</em>:                              70=x
  6. Rewrite:                               x=70

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                   \frac{0.35}{\frac{2}{3}(70) } =\frac{0.45}{70-10}
  2. Multiply:                       \frac{0.35}{\frac{140}{3}  } =\frac{0.45}{70-10}
  3. Subtract:                      \frac{0.35}{\frac{140}{3}  } =\frac{0.45}{60}
  4. Evaluate:                     0.0075=0.0075
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What is the probability that more than twelve loads occur during a 4-year period? (Round your answer to three decimal places.)
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