Answer:
A. 12.68 - 14.72 hours
B. Normal distribution.
Step-by-step explanation:
Part A
This question is using quantitative data. A 99% confidence interval means that you want to know the range where 99% of the population will be. To find this you have to convert the 99% CI into the z-score which is -2.58SD to + 2.58SD.
Note that the standard deviation(SD) is from the sample, not the population. We still need to find the standard deviation of the population. The formula is:
population SD = ![\frac{o}{\sqrt[]{n} }](https://tex.z-dn.net/?f=%5Cfrac%7Bo%7D%7B%5Csqrt%5B%5D%7Bn%7D%20%7D)
Where the o= sample SD = 7.4
n= number of sample = 463
The calculation will be:
population SD = ![\frac{o}{\sqrt[]{n} }](https://tex.z-dn.net/?f=%5Cfrac%7Bo%7D%7B%5Csqrt%5B%5D%7Bn%7D%20%7D)
population SD =
= 0.3951
The bottom limit will be:
Mean - SD * z-score= 13.7 - 0.3951*2.58 = 12.68 hours
The upper limit will be:
Mean + SD * z-score= 13.7 + 0.3951*2.58 =14.72 hours
The 99% CI range will be 12.68 - 14.72 hours
Part B
The table used to convert confidence interval into z-score depends on the distribution type of the data. Most data is classified as normal distributed, a data type that will concentrated at mean and spread equally from the mean. Normal distribution data will look like a bell which make it also called bell curve.
The question tells you that the data is normal distribution, but that doesn't mean every data is normally distributed. There are a lot of other data distribution type so we have to do some tests to know the normality of the data in real-life data.
Answer:
y=-2x+11
Step-by-step explanation:
I'm not 100% sure. sorry <3
Answer:
Option A.
Step-by-step explanation:
It is given that
The given expression is
Substitute the given values in the above expression.
Therefore, the correct option is A.
Answer:
combined velocity of the system = 0.033 m/s.
Step-by-step explanation:
taking the bullet and block as single system since there is no external force involved momentum is conserved .
initial momentum of the bullet = mv
where m is the mass of bullet and v is velocity of bullet.
and initial momentum of block = 0 since its velocity is 0.
therefore initial momentum of the system = mv
= 0.005×40
= 0.2
when the bullet stick of together with the block let the combined velocity of the system be V
therefore applying conservation of momentum
mv = (M+m)V
0.2=(6+0.005)V
therefore V = 0.033 m/s
(X-5)(2x+3) hope this helps