What is the standard form of the equation of a circle with the radius ( r=6) and the center (h,k)= (0,0)?

Stella [2.4K]

Answer:

Identity (a) can be re-written as

$sec x\ cosec x - cot x = tan x$

which we already proven in another question, while for idenity (b)

$(A)\frac 1 {sin x} -sin x = cos x \frac{cos x}{sin x}\\\\(B)\frac {1-sin^2x}{sin x} = \frac {cos^2x} {sin x} \\\\(C) \frac {cos^2x}{sin x} =\frac {cos^2x} {sin x}$

step A is simply expressing each function in terms of sine and cosine.

step B is adding the terms on the LHS while multiplying the one on RHS.

step C is replacing the term on the numerator with the equivalent from the pithagorean identity $cos^2x + sin^2x = 1$

8 0

1 year ago

PLEASE HELP WILL MARK BRAINLIEST!!!!!! Base the question off this info: An experienced cashier at a grocery store takes 2 second

Vesna [10]

You need to use basic algebra for this.
For this I’ll use o as the items and p for the payment. First you need to find out how long it took for all the items to scan, so if it took each item 2 seconds to be scanned you need to times the total number of items (o) by two e.g. o x 2 = 62 items times two seconds which is equivalent to 62 seconds (1.02 minutes) after this step you need to minus the total time it took to scan the items for the transaction time (2 minutes) e.g. 2.00 - 1.02 = 2.58 minutes.

Hope this helped :)

3 0

2 years ago

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Help with this question

Sholpan [36]

With some simplification,

cos⁻¹(x) - 5 cos⁻¹(x) - π/3 = 2π/3

becomes

-4 cos⁻¹(x) = π

or

cos⁻¹(x) = -π/4

However, the inverse cosine function has a range of 0 ≤ cos⁻¹(x) ≤ π, so there are no solutions to this equation.

4 0

2 years ago

The functions f(x) = −(x − 1)2 5 and g(x) = (x 2)2 − 3 have been rewritten using the completing-the-square method. apply your kn

ale4655 [162]

The vertex of the function f(x) exists (1, 5), the vertex of the function g(x) exists (-2, -3), and the vertex of the function f(x) exists maximum and the vertex of the function g(x) exists minimum.

<h3>How to determine the vertex for each function is a minimum or a maximum? </h3>

Given:

$\mathrm{f}(\mathrm{x})=-(\mathrm{x}-1)^{2}+5$ and