Answer:
Identity (a) can be re-written as

which we already proven in another question, while for idenity (b)

step A is simply expressing each function in terms of sine and cosine.
step B is adding the terms on the LHS while multiplying the one on RHS.
step C is replacing the term on the numerator with the equivalent from the pithagorean identity 
You need to use basic algebra for this.
For this I’ll use o as the items and p for the payment. First you need to find out how long it took for all the items to scan, so if it took each item 2 seconds to be scanned you need to times the total number of items (o) by two e.g. o x 2 = 62 items times two seconds which is equivalent to 62 seconds (1.02 minutes) after this step you need to minus the total time it took to scan the items for the transaction time (2 minutes) e.g. 2.00 - 1.02 = 2.58 minutes.
Hope this helped :)
With some simplification,
cos⁻¹(x) - 5 cos⁻¹(x) - π/3 = 2π/3
becomes
-4 cos⁻¹(x) = π
or
cos⁻¹(x) = -π/4
However, the inverse cosine function has a range of 0 ≤ cos⁻¹(x) ≤ π, so there are no solutions to this equation.
The vertex of the function f(x) exists (1, 5), the vertex of the function g(x) exists (-2, -3), and the vertex of the function f(x) exists maximum and the vertex of the function g(x) exists minimum.
<h3>How to determine the vertex for each function is a minimum or a maximum? </h3>
Given:
and

The generalized equation of a parabola in the vertex form exists

Vertex of the function f(x) exists (1, 5).
Vertex of the function g(x) exists (-2, -3).
Now, if (a > 0) then the vertex of the function exists minimum, and if (a < 0) then the vertex of the function exists maximum.
The vertex of the function f(x) exists at a maximum and the vertex of the function g(x) exists at a minimum.
To learn more about the vertex of the function refer to:
brainly.com/question/11325676
#SPJ4
Answer:
-6
-21
12
Step-by-step explanation:
can i get brainly