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Gemiola [76]
3 years ago
9

$sam's\:mother\:is\:twice\:as\:old\:as\:sam.\:in\:12\:years\:sam\:will\:be\:as\:old\:as\:his\:mother\:was\:12\:years\:ago.\:how\

:aod\:are\:sam\:and\:his\:mother$

Mathematics
1 answer:
Furkat [3]3 years ago
8 0

9514 1404 393

Answer:

  Sam is 24; his mom is 48.

Step-by-step explanation:

We can let x and y represent Sam's age and his mom's age, respectively.

  y = 2x . . . . . Mom is twice Sam's age

  y -12 = x + 12 . . . . Mom's age 12 years ago is the same as Sam's age 12 years from now

__

Substituting for y in the second equation, we have ...

  2x -12 = x + 12

  x = 24 . . . . . . . . . add 12-x to both sides

  y = 2(24) = 48

Sam is 24; his mom is 48.

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Please answer this and I’ll make ya
Fynjy0 [20]
It’s definitely A
Ex: f(x)=8x+2
f(x)=8(-4)+2
f(x)=-32+2
f(x)=-30
3 0
3 years ago
Find the surface area of the figure?
motikmotik

Step-by-step explanation:

the surface area consists of 6 individual areas :

front and back (both are equal)

left and right (both are equal)

top and bottom

front and back are trapezoids.

the area of a trapezoid is

(base 1 + base 2)/2 × h

the bases are the 2 parallel sides.

in our case the area of one trapezoid is

(5 + 19)/2 × 12.1 = 145.2 ft²

front and back together then are 290.4 ft².

left and right are 8×14 rectangles:

8×14 = 112 ft²

together they are 224 ft².

the bottom is a 5×8 rectangle :

5×8 = 40 ft²

the top is a 19×8 rectangle :

19×8 = 152 ft²

so, the total surface area is

290.4 + 224 + 40 + 152 = 706.4 ft²

4 0
2 years ago
Factorize the following expressions
klio [65]

Step-by-step explanation:

1. a² - ( b ² - 2bc + c² ) = a ² - b ² + 2bc - c²

2. 8p² - 18 q²

3. 3ab² - c²d + 3ab - b²c²

4. x² - 2x + 1

8 0
3 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
2 years ago
Select all the correct answers.
Phantasy [73]

Answer:

a = 6, b = 8, and c = 10.

Step-by-step explanation:

You can easily use the Pythagorean Theorem to solve all of these.

a = 4; b = 6; c = 8... 4^2 + 6^2 = 16 + 36 = 52. 8^2 = 64. 52 is not equal to 64, so the first choice is not a right triangle.

a = 6; b = 8; c = 10... Well this is a multiple of the 3-4-5 Pythagorean triple, so this is a right triangle.

a = 5; b = 6; c = 761... 5^2 + 6^2 = 25 + 36 = 61. 761^2 = 579121, which is not equal to 61, so the third choice is not a right triangle.

a = 6; b = 9; c = 12... 6^2 + 9^2 = 36 + 81 = 117. 12^2 = 144, which is not equal to 117, so the fourth choice is not a right triangle.

The only case where there is a right triangle is the second choice, where a = 6, b = 8, and c = 10.

Hope this helps!

3 0
3 years ago
Read 2 more answers
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