The answer would be 11.
He’s playing 6 games to meet his goal which is 600. Adding 105+95+97+82+110 you’ll have 489 total points. You’ll then subtract 600-489 which will equal to 111.
Answer:
You can do these "in your head" like this:
50 dimes would be $5.00
Each quarter adds 15 cents.
10.25 - 55.00 = $5.25 added
Step-by-step explanation:
525/15 = 35 quarters
--> 15 dimes
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or,
d + q = 50
10d + 25q = 1025
etc
Let's say the number of days library book is late is X, and the total fee is Y.
Liability charges $0.30 dollars as a fee for being 1 day late,
For being 1 day late, fee charge is: 1* $0.30
So, for X days the charge would be: X*$0.30.
Total charge for being X days late is Y, Which means: Y= 0.30 * X.
Now We would have to check all the viable solutions in the answer to see if they satisfy the equation Y= 0.30 * X
Option one(-3, -0.9) and two (-2.5, -0.75) Would not be a viable solution because the value of number of days can not be negative and in option one and two, value of days -3 and -2.5 is negative.
Option three(4.5, 1.35) can not be correct because library charges fee for a full day so the number for days would be a whole number. Library would not charge for 4.5 days, they would either charge of 4 days or 5 days because 4.5 is not an whole number.
Option four(8, 2.40) is the correct answer because it satisfies our equation;
Y= 0.30 * X
2.40= 0.30 * 8
2.40 = 2.40.
Fourth option (8, 2.40) is the only viable solution to this question.
I think it's D. Hope this helps! Let me know if it's correct.
Let initially number of fishes =x
He gives 2/3 of his fish to a local high school, that is he gives 2x/3 fish .
So number of fishes left = x -(2x/3) = x/3 . And he gives 2/5 of x/3 to an elementary school , that is , he gives 2x/15 fishes to the elementary school. And finally the number of fishes left =30 , that is
So initially he have 150 fishes .
