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Misha Larkins [42]
3 years ago
7

Find the greatest common factor of 25 and 33 .

Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0
Factor and find commmon ones
25=1*5*5
33=1*3*11

GCF=1
(I am noticing that GCF=1 for many of your questions)
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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
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Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
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If you sell 3 bags of candy, then 4 bags and finally 1 bag, how much is each bag if you collected $6.40?
mariarad [96]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

=> 78% makes:

=> \frac{78}{100}

<u><em>In simplest form:</em></u>

=>\frac{39}{50}

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Answer:

Answers A (1/3), C (4/15) and D (5/6) are all repeating decimals.  

Step-by-step explanation:

Repeating decimals are decimals in which a number or sequence of numbers is repeated over and over when dividing the numerator by the denominator of a fraction.  For example, when you divide 1 by 3 (1/3), you will get a repeating decimal of 0.3333...since 3 goes into 10 three times with a remainder of 1 and will keep going.  Likewise, when you divide 4/15, you get an initial value of 0.2, with a repeating 6, or 0.266666...  Lastly, when you divide 5/6, you will get a repeating decimal of 0.833333....  The other answers will all be terminating decimals when you divide the numerator by the denominator.  Terminating decimals mean the stop at some point and don't continue.  

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