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3 years ago

What is the value of the expression =2 ? 0 2

Mathematics

2 answers:

Valentin [98]3 years ago

6 0

2 is the answer because 2=2 but 2 doesn’t =0.

Naddik [55]3 years ago

5 0

The answer is 2 because 2=2

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Can you help me please ?

rewona [7]

(Create a table then plot the points)

X | 0 | 1 | 2 | 3 |

-------------------------

Y | -1 | 3 | 7 | 11 |

4 (0) -1 => 0 - 1 = -1

4 (1) -1 => 4 - 1 = 3

4 (2) -1 => 8 - 1 = 7

4 (3) -1 => 12 - 1 = 11

Just apply the table method to the others and you should be fine! :)

8 0

3 years ago

What is the equation in point-slope form of the line passing through (−2, 0) and (2, 8)? (1 point) y = 2(x + 2) y = 2(x − 2) y =

Sonja [21]

Answer: $y=2(x+2)$

Step-by-step explanation:

The slope of the line is

$y=\frac{8-0}{2-(-2)}=\frac{8}{4}=2$

Using the point (-2, 0) to substitute into point-slope form, we get the equation to be $\boxed{y=2(x+2)}$

8 0

1 year ago

Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =

vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

$a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2$

$a_1=8$

Find the value of $a_2$

For n=2

$a_2=2.9(a_1)-0.2(a_1)^2$

$a_2=2.9(8)-0.2(8)^2=10.4$

Find the value of $a_3$

For n=3

$a_3=2.9(a_2)-0.2(a_2)^2$

$a_3=2.9(10.4)-0.2(10.4)^2=8.528$

For n=4

$a_4=2.9(a_3)-0.2(a_3)^2$

$a_4=2.9(8.528)-0.2(8.528)^2=10.1858$

For n=5

$a_5=2.9(a_4)-0.2(a_4)^2$

$a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887$

therefore

The population alternates between increasing and decreasing

7 0

3 years ago

Read 2 more answers

HELP me help help help help

Ad libitum [116K]

2x+79+32=180
2x+111=180
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2 years ago

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Taya2010 [7]

A: (450>/10)+5
B: 44 Students

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3 years ago

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