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3 years ago

HELP ASAP PLEASE!!! MARKING BRAINIEST!!!.

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

8 0

Answer:

9.4%

Step-by-step explanation:

wolverine [178]3 years ago

3 0

Answer:

9.4

Step-by-step explanation:

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A flight from Boston to London took only 5 hours because of a strong tailwind. The flight back to Boston against the same wind t

Nata [24]

Step-by-step explanation:

let v is the speed of the wind,

the equation of the speed:

(550 + v ) × 5 = (550 - v) × 6

2750 +5v = 3300 - 6v

11v = 3300 - 2750

11v = 550

v = 550/11

v = 50

therefore, the speed of the wind =

50 mph

3 0

3 years ago

Read 2 more answers

A performing arts theater offers a group rate om season passes of $70 total for the first two passes plus $25 for each additiona

emmainna [20.7K]

Answer:

$220.00

Step-by-step explanation:

$70 dollars for 2

$25x6

$70+$150=$220.00

6 0

3 years ago

Find x please 10.3 9.6 84 9

valentinak56 [21]

The 2 small black lines through the sides of the triangle indicate that the 2 sides are the same length.

Because the 2 sides are the same the 2 bottom angles are also the same.

This means that 9x +3 = 84

Now we can solve for x:

9x +3 = 84

Subtract 3 from each side:

9x = 91

Divide both sides by 9:

x = 81 / 9

x = 9

4 0

4 years ago

0.4(35m-30n) do you know this

soldier1979 [14.2K]

All you have to do is to multiply 35m and -30n by 0.4, one by one, to produce two terms separated by a " _ " symbol.

6 0

4 years ago

Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.

Evgesh-ka [11]

A="b is in the middle"

B="c is to the right of b"

C="The letter def occur together in that order"

a) b can be in 7 places, but only one is the middle. So, P(A)=1/7

b) X=i, "b is in the i-th position"

Y=j, "c is in the j-th position"

$P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}$

P(B)=1/2

c) X=i, "d is in the i-th position"

Y=j, "e is in the j-th position"

Z=k, "f is in the i-th position"

$P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}$

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

$P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420$

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

A and C aren't independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

B and C aren't independent

8 0

3 years ago