❤️Hello!❤️For experimental data it may be good to use linear regression.
For precise data you do not need linear regression.
Step-by-step explanation: If you have a number of experimentally generated data points that are subject to inaccuracies then you can use something like linear regression to generate a linear model that fits the data reasonably well. Many modern calculators have a linear regression capability.
On the other hand, if you are given precise data, you should be able to generate a model that fits the data exactly. For example, given points (
x
1
,
y
1
) and (
x
2
,
y
2
) which are supposed to lie on a line, the equation of the line in point-slope form is:
y
−
y
1
=
m
(
x
−
x
1) where m
=
y
2
−
y
1
x
2
−
x
1 from which we can derive the slope-intercept form:
y
=
m
x
+
c where c
=
y
1
−
m
x
1. ☯️Hope this helps!☯️ ↪️ Autumn ↩️
Plot point(0,-6). Then go down 1 and 1 to the right locate another point(1,-7) connect (0,-6) and(1,-7) and extended from both sides
Answer:
B
Step-by-step explanation:
3(20)=60
2(30)=60
60+60=120
2(20)= 40
4(30)= 120
40+120=160
Answer:
126
Step-by-step explanation:
word your question a little better next time this was almost illegible.