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3 years ago

Which equation represents the graphed function

Mathematics

2 answers:

ss7ja [257]3 years ago

7 0

Answer:

I'd love to answer but need more data...

goblinko [34]3 years ago

6 0

I cannot answer that, as I do not have the graph and need more info to answer.

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Please help and show work thank you.

vichka [17]

An equilateral triangles has 3 equal sides and 3 equal angles.
All the angles of an equilateral triangle have a measure of 60 degrees.

Using the Pythagorean theorem, the length of the hypotenuse squared is the length of one leg squared plus the length of another leg squared.

Here's the equation for the Pythagorean theorem.
Let c be the length of the hypotenuse.
Let a and b be the length of the two legs.
a^2 + b^2 = c^2

Have an awesome day! :)

7 0

3 years ago

Read 2 more answers

What is 21 > 15 + 2a

raketka [301]

My bests answer I got was a<3

5 0

3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Mkey [24]

For this case, we have to:

By definition, we know:

The domain of $f (x) = \sqrt [3] {x}$ is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

$y = \sqrt [3] {x-2}$ with $x = 0$ : $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x+2}$ with $x = 0:\ y = \sqrt [3] {2}$ is also defined.

$f (x) = \sqrt {x}$ has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x+2}$ if it is defined for $x = 0$ .

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago

Which of the following is correct equation for the trend line in the scatter plot? A. Y= 2/5 x -2 B. Y= 5x-1 C. Y= 5x +5 D. Y= -

Dafna11 [192]

Answer: C. Y = 5x + 5

Step-by-step explanation:

We need to write, or decide on, the equation for the blue line as this line represents the trend line for this scatter plot. We will write this in slope-intercept form. See attached for a visual.

First, we will find our slope. We will use $\frac{rise}{run}$ for this since we have a graph with clear points. See attached, we count up [5] and then count to the right [1] for a slope of 5.

-> Slope = 5

Now, we will find our y-intercept. This is where the line intersects the y-axis. The line hits the y-axis at point (0, 5) giving us a y-intercept of 5.

-> Y-intercept = 5

Lastly, we will write our equation and decide on an answer.

y = mx + b

y = (5)x + (5)

Y = 5x + 5

C. Y = 5x + 5