360 - 4x - (x+40) - (x+10) = A
A = 360 - 4x - x - 40 - x - 10
A = 310 - 6x
A = 142
Answer:
Jamal travels at a speed of 5 mph and Diego travels at a speed of 12 mph.
Step-by-step explanation:
Jamal's speed is of x mph.
Diego's speed is of (x + 7) mph.
Opposite directions.
This means that each hour, they will be x + x + 7 = 2x + 7 miles apart.
After 4 hours they are 68 miles apart, how fast is each traveling?
Using a rule of three.
1 hour - 2x + 7 miles apart.
4 hours - 68 miles apart.
![4(2x + 7) = 68](https://tex.z-dn.net/?f=4%282x%20%2B%207%29%20%3D%2068)
![8x + 28 = 68](https://tex.z-dn.net/?f=8x%20%2B%2028%20%3D%2068)
![8x = 40](https://tex.z-dn.net/?f=8x%20%3D%2040)
![x = \frac{40}{8}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B40%7D%7B8%7D)
![x = 5](https://tex.z-dn.net/?f=x%20%3D%205)
Jamal travels at a speed of 5 mph and Diego travels at a speed of 12 mph.
Answer:
y = (-3/4)x + 15
Step-by-step explanation:
The slope of the given line is 4/3. The slope of a line perpendicular to this given line is the negative reciprocal of 4/3, which comes out to -3/4.
Now that we have both the slope and y-intercept of the new line, we're ready to write out the desired equation in slope-intercept form:
y = (-3/4)x + 15
√9 = 3 and is rational
Its C
Using the relation between velocity, distance and time, it is found that he traveled 281.25 km by bus and 1618.75 km by plane.
<h3>What is the
relation between velocity, distance and time?</h3>
Velocity is distance divided by time, that is:
![v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
In this problem, first he traveled a distance of d km by bus, with an average speed of 60 km/h and a time of t, hence:
![60 = \frac{d}{t}](https://tex.z-dn.net/?f=60%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
![d = 60t](https://tex.z-dn.net/?f=d%20%3D%2060t)
Then, by plane, he traveled a distance of 1900 - d km, with an average speed of 700 km/h and a time of 7 - t, hence:
![700 = \frac{1900 - d}{7 - t}](https://tex.z-dn.net/?f=700%20%3D%20%5Cfrac%7B1900%20-%20d%7D%7B7%20-%20t%7D)
Since d = 60t, we have that:
![700 = \frac{1900 - 60t}{7 - t}](https://tex.z-dn.net/?f=700%20%3D%20%5Cfrac%7B1900%20-%2060t%7D%7B7%20-%20t%7D)
![1900 - 60t = 4900 - 700t](https://tex.z-dn.net/?f=1900%20-%2060t%20%3D%204900%20-%20700t)
![640t = 3000](https://tex.z-dn.net/?f=640t%20%3D%203000)
![t = \frac{3000}{640}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B3000%7D%7B640%7D)
![t = 4.6875](https://tex.z-dn.net/?f=t%20%3D%204.6875)
Hence:
d = 60t = 60 x 4.6875 = 281.25 km
1900 - d = 1900 - 281.25 = 1618.75 km
He traveled 281.25 km by bus and 1618.75 km by plane.
More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569