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MA_775_DIABLO [31]
4 years ago
5

Who thinks they could do a realistic cat drawling in 10 minutes?!? i can!

Mathematics
1 answer:
Mashutka [201]4 years ago
3 0
I think that I can ..................
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Solve the equation <br> 3= x/6 + 1
dangina [55]

Answer:

x = 12

Step-by-step explanation:

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List all the subsets of each set:<br><br> {a,e,i, o}
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\{\}, \{a\}, \{e\}, \{i\}, \{o\}, \{a, e\}, \{a, i\}, \{a, o\}, \{e, i\}, \{e, o\}, \{i, o\}, \{a, e, i\},\\&#10; \{a, e, o\}, \{a, i, o\}, \{e, i, o\}, \{a, e, i, o\}
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Please help fast will give 5 stars and thank you
aniked [119]

Answer:

(1,-1)

Step-by-step explanation:

Hope it helps

7 0
4 years ago
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Lucy's dog weighs nine and seventy five hundredths kilograms . Write in expanded form.
MissTica
<span>9 + 0.07 + 0.005 this is expanded form  i hope this is what u wanted as an answer</span>
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3 years ago
Determine what type of model best fits the given situation: An Internet phone company presently provides service to 5,000 custom
bagirrra123 [75]

Answer:

The best fit is <em>A. Linear model</em>

<em></em>

Step-by-step explanation:

Given:

Monthly Rate = $20, Number of customers = 5000

If there is a decrease of $1 in the monthly rate, the number of customers increase by 500.

To find:

The type of model that best fits the given situation?

Solution:

Monthly Rate = $20, Number of customers = 5000

Let us decrease the monthly rate by $1.

Monthly Rate = $20 - $1  = $19, Number of customers = 5000 + 500 = 5500

Let us decrease the monthly rate by $1 more.

Monthly Rate = $19 - $1  = $18, Number of customers = 5500 + 500 = 6000

Here, we can see that there is a <em>linear change </em> in the number of customers whenever there is decrease in the monthly rate.

We have 2 pair of values here,

x = 20, y = 5000

x = 19, y = 5500

Let us write the equation in slope intercept form:

y =mx+c

Slope of a function:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{5500-5000}{19-20}\\\Rightarrow -500

So, the equation is:

y =-500x+c

Putting x = 20, y = 5000:

5000 =-500\times 20+c\\\Rightarrow c = 5000 +10000 = 15000

\Rightarrow \bold{y =-500x+15000}

Let us check whether (18, 6000) satisfies it.

Putting x = 18:

-500 \times 18 +15000 = -9000+15000 = 6000 so, it is true.

So, the answer is:

The best fit is <em>A. Linear model</em>

6 0
4 years ago
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