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3 years ago

Which graph represents this equation?

Mathematics

1 answer:

zheka24 [161]3 years ago

5 0

The graph in the bottom left is correct

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Can someone help me will give brainlist

MissTica

Answer:
I only know the first one...
C) 4896
Step-by-step explanation:
For the first pick, 18 students to pick from then 17 left and then 16 left.

18 * 17 * 16 = 4896

8 0

2 years ago

A functionf(x) is graphed on the coordinate plane.

AleksandrR [38]

The function rule in slope-intercept form is y = -4x -2

<h3>What is a function ?</h3>

A function is defined as the mathematical statement which defines relation between a dependent variable and an independent variable.

A function f(x) is graphed on the coordinate plane.

The equation for a straight line is given by

y = mx + c

Where m is the slope and c is the intercept on y axis

The intercept on y axis is -2

c = -2

At x = 0 , y =-2

At x = -1 , y =2

m =(2 -(-2))/(-1-0)

m = -4

Therefore ,the function rule in slope-intercept form is y = -4x -2 .

To know more about Function

brainly.com/question/12431044

#SPJ1

3 0

2 years ago

The 15th term of an arithmetic series is

RSB [31]

Answer:

-1557

Step-by-step explanation:

a+14d=143

a+12d=183

--------------------

2d= -40

d= -20

a=183+240=423

a(100th)= 423+99*-20=423-1980= -1557

I hope that help =)

7 0

2 years ago

What is the turning point of the graph of f(x)=(x+2)-3

Naddika [18.5K]

<span>b. f(x) = x^2 -4x -5 i think</span>

8 0

3 years ago

A fair coin is tossed three times and the events A, B, and C are defined as follows: A:{ At least one head is observed } B:{ At

kicyunya [14]

Answer:

(a) 1/2

(b) 1/2

(c) 1/8

Step-by-step explanation:

Since, when a fair coin is tossed three times,

The the total number of possible outcomes

n(S) = 2 × 2 × 2

= 8 { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT },

Here, B : { At least two heads are observed } ,

⇒ B = {HHH, HHT, HTH, THH},

⇒ n(B) = 4,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

(a) So, the probability of B,

$P(B) =\frac{n(B)}{n(S)}=\frac{4}{8}=\frac{1}{2}$

(b) A : { At least one head is observed },

⇒ A = {HHH, HHT, HTH, THH, HTT, THT, TTH},

∵ A ∩ B = {HHH, HHT, HTH, THH},

n(A∩ B) = 4,

$\implies P(A\cap B) = \frac{n(A\cap B)}{n(S)} = \frac{4}{8}=\frac{1}{2}$

(c) C: { The number of heads observed is odd },

⇒ C = { HHH, HTT, THT, TTH},

∵ A ∩ B ∩ C = {HHH},

⇒ n(A ∩ B ∩ C) = 1,

$\implies P(A\cap B\cap C)=\frac{1}{8}$

7 0

3 years ago