According to question,
= 8x² + 6x - 2 = 228
= 8x² + 6x - 230 = 0
= 2(4x² + 3x - 115) = 0
= 2(4x² + 23x - 20x - 115) =0
= 2(x(4x +23) -5(x - 23) )= 0
= 2((x-5)(4x+23)) = 0
x = 5 , x = -23/4
let x = 5
so length 4x - 1
= 4 × 5 - 1
= 19 ft
width = 2x + 2
= 2 × 5 + 2
= 22 ft
_______
gosh! finally did it.. was too big -_-
Answer:
A.: x=-4
b.:x=4
c.:y=4
d.:y=-2
e.:y= -3/4x + 1
Step-by-step explanation:
I like these kind of problems and I am great at them! Ask me these anytime you need!
Answer:
x-intercept: 1
C is correct
Step-by-step explanation:
A line has a slope of –3 and a y-intercept of 3
Slope (m) = -3
y-intercept: (0,3)
Using slope and y-intercept we will make the equation of line.
Equation of line:
Now we will find x-intercept
For x-intercept put y=0
x-intercept: (1,0)
Hence, The x-intercept of the equation is 1
a parallel line to that equation will have the same exact slope, so
then we're really looking for the equation of a line whose slope is -3, and runs through (-5,-8)
![\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = m\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=-3[x-(-5)] \\\\\\ y+8=-3(x+5)\implies y+8=-3x-15\implies y=-3x-23](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-5%7D~%2C~%5Cstackrel%7By_1%7D%7B-8%7D%29~%5Chspace%7B10em%7D%20slope%20%3D%20m%5Cimplies%20-3%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%28-8%29%3D-3%5Bx-%28-5%29%5D%20%5C%5C%5C%5C%5C%5C%20y%2B8%3D-3%28x%2B5%29%5Cimplies%20y%2B8%3D-3x-15%5Cimplies%20y%3D-3x-23)
Answer:
2
Step-by-step explanation:
(4 - 5) - (13 - 18 + 2)
According to PEMDAS, we should simplify the parentheses first.
= (-1) - (-3)
When you subtract a negative number, you are actually adding.
= -1 + 3
Now, add.
= 2
Hope this helps!
