Answer: C)14,000 + 5,600 + 70 + 21
Step-by-step explanation:
2813=2000+800+10+3
2000*7=14000
800*7=5600
10*7=70
3*7=21
i hope it help ο(=•ω<=)ρ⌒☆
All I can see is the equation. What is it asking?
Answer:
7.3% percentage of the bearings produced will not be acceptable.
Step-by-step explanation:
Consider the provided information.
Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.
Let X is the normal random variable which represents the diameter of bearing.
Thus, 0.500-0.004<X<0.500+0.004
0.496<X<0.504
The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.
Use the Z score formula: 
Therefore



Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.
We need to find the percentage of the bearings produced will not be acceptable.
So subtract it from 1 as shown.
1-0.9270=0.073
Hence, 7.3% percentage of the bearings produced will not be acceptable.
4)
area of figure = bh = 8x10 = 80
same as a trapezoid have base 6 and 14 and height 8
because A of trapezoid = 1/2(6+14)*8 = 80
so answer is C
a trapezoid with bases of 6 mm and 14 mm and a height of 8 mm
5)
area of original figure A = bh = 8 x 10 = 80
if double h = 16 and b = 20 then A = 16 x 20 = 320
the area is quadrupled.
answer is C.
The area is quadrupled