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garri49 [273]
3 years ago
9

36d^3+24 solve please.

Mathematics
2 answers:
Oduvanchick [21]3 years ago
5 0
The answer is:

12 (3d^3 + 2)

pls mark as brainlist!!
Sergeeva-Olga [200]3 years ago
3 0

Solution, 36d^3+24:\quad 12\left(\sqrt[3]{3}d+\sqrt[3]{2}\right)\left(3^{\frac{2}{3}}d^2-\sqrt[3]{6}d+2^{\frac{2}{3}}\right)

Steps:

36d^3+24

\mathrm{Factor\:out\:common\:term\:}12,\\12\left(3d^3+2\right)

\mathrm{Factor}\:3d^3+2,\\12\left(\sqrt[3]{3}d+\sqrt[3]{2}\right)\left(\left(\sqrt[3]{3}\right)^2d^2-\sqrt[3]{2}\sqrt[3]{3}d+\left(\sqrt[3]{2}\right)^2\right)

\mathrm{Refine},\\12\left(\sqrt[3]{3}d+\sqrt[3]{2}\right)\left(3^{\frac{2}{3}}d^2-\sqrt[3]{6}d+2^{\frac{2}{3}}\right)

Hope\:This\:Helps!!!

-Austint1414

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Answer:

Step-by-step explanation:

Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.

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<em></em>

<em>b) </em>If if 223ₓ = 87 find x

Using the number base system and converting 223ₓ  to base 2 will give us;

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​

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<em>Hence the value of x is 7 (neglecting the negative value)</em>

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