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3 years ago

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Mathematics

1 answer:

zavuch27 [327]3 years ago

4 0

Answer:

c. 4y=6x+8

Step-by-step explanation:

For lines to be parallel, they must have the same slope. To solve this problem, we need to isolate the y on one side of the equation (putting the equation into slope intercept form).

The equation itself must be divided by 2 to do that. We end up with y=1.5x-0.5. We need to find another equation that has 1.5 as the slope.

b. y=0.5x-1.5

c. y=1.5x+2

d. y=3x+4

e. y=2/3x-1

As we can see, the only other equation with a slope of 1.5 is C. Therefore, C is our answer.

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Help pls and explain!!

quester [9]

Answer:

100

Step-by-step explanation:

$(100 \times 3) - (100 \times 2) = 100$

4 0

3 years ago

In right triangle ABC, A=15°, C=37, and angle C is the right angle. Solve the triangle. Round to the nearest tenth, if necessaar

Mice21 [21]

Answer:

180 degrees

Step-by-step explanation:

The sum of the interior angles of a triangle is 180 degrees. Since angle C is 90 degrees and angle A is 15 degrees Then,

A+B+C=180

15+90+B=180

B=180-90-15

B=75 degrees

Using the sine law,

a/sinA = b/sinB = c/sinC

where a, b, and c are the sides of the triangle,

So,

a/sin15 = 37/sin90

and

b/sin75 = 37/sin90

Simplifying, and solving for a and b, the measure of each side is

a= 9.58 units

b=35.74 units

I hope this helped. I am sorry if you get this wrong.

5 0

3 years ago

How do I solve |x-1|-1.4 = 6.2

just olya [345]

Answer:

x1= -6.6 x2= 8.6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Need help. thank you

yulyashka [42]

Answer:

x = 70.53 degrees

Step-by-step explanation:

equation:

cos-1 = $\frac{adjacent}{hypotenuse}$

⇒ cos-1 x = $\frac{4}{12}$

⇒ cos-1 x = 0.33

⇒ x = 70.528

round to the nearest tenth:

⇒ 70.53

7 0

3 years ago

Read 2 more answers

In how many ways can a set of two nonnegative integers less than 100 be chosen?

hichkok12 [17]

Answer: 4950

Step-by-step explanation:

The number of possible combinations of n things taken r at a time is given by :-

$C(n,r)=\dfrac{n!}{r!(n-r)!}$

Total nonnegative integers less than 100 ={0,1,2,... ,99} = 100

So, the number of combinations of choosing 2 out of them = $C(100,2)=\dfrac{100!}{2!98!}=\dfrac{100\times99\times98!}{2\times98!}\\\\=\dfrac{100\times99}{2}\\\\=50\times 99\\\\=4950$

So, the number of ways to choose a set of two nonnegative integers less than 100 = 4950

5 0

3 years ago