The answer is 3,072.
Heres how I got it:
SA of a CUBE: s^3 * 6
Lets plug in our numbers-
8 * 8 * 8= 512 * 6
512 * 6= 3072
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Answer: (4) 14
Step-by-step explanation:
8x - 2y if x is 3 and y is 5
8x = 24
2y = 10
24 - 10 = 14
So 8x - 2y is 14.
Answer:
10.6
Step-by-step explanation:
4 + 6(1.3) - 2.4 * 0.5
= 4 + 6 * 1.3 - 2.4 * 0.5
= 4 + 7.8 - 0.5 * 2.4
= 4 + 7.8 - 1.2
= 10.6
