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Neporo4naja [7]
3 years ago
14

What are some non-examples of deposition, erosion, and weathering? I need at least 4 examples each...

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0
Coal cause when you burn it it is gone hope I helped
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What's -9 x 7 plssssssssss answerrrrr quicklyyyy
NNADVOKAT [17]
It’s -63 all you would be multiple like normal 63 which then you put a negative symbol on front
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3 years ago
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A rope is 72 feet long. What is the length of the rope in yards
Lostsunrise [7]
The answer would be 24 yards. This would be 24 because 3 feet equal one yard so 3/72 is 24 or 24•3.
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3 years ago
At 5.45p.M .,lixin,khairul and Devil are at the starting point of a 1-km circular path. Lixin Takes 18 minutes to walk one round
sweet [91]

Answer:

Meeting\ Time = 6:03\ pm

Step-by-step explanation:

Given

Start\ Time= 5:45pm

Lixin = 18\ min/round

Khairul = 360\ seconds/round

Devi = 4minutes/2\ rounds

Required

Determine their next meeting time

First, we need to get their unit rate in minutes per round

Lixin = 18\ min/round

Khairul = 360\ seconds/round

Convert 360 seconds to minutes

Khairul = \frac{360}{60} min/round

Khairul = 6 min/round

Devi = 4minutes/2\ rounds

Divide by 2/2

Devi = 2mins/round

So, we have:

Lixin = 18\ min/round

Khairul = 6 min/round

Devi = 2mins/round

Next, is to determine the LCM of 18, 6 and 2

18=2 * 3 * 3

6 = 2 * 3

3 = 3

Their LCM is:

LCM = 2 * 3 * 3

LCM = 18

This means that they will meet 18 minutes after their initial time of departure.

So:

Meeting\ Time = 5:45\ pm + 18\ minutes

Meeting\ Time = 6:03\ pm

3 0
3 years ago
10TH GRADE GEOMETRY, REAL ANSWERS PLS. HELP :)
lisov135 [29]
(B) is the right answer
5 0
3 years ago
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Working simultaneously, four fudge machines complete a big order in 32 hours. All the machines at the fudge factory work at the
Alinara [238K]

Answer:

4 Hours

Step-by-step explanation:

Let's say that the rate of the machines 1/x, because every time they complete an order, it takes them x hours. To find x, we have to add the the rates of the individual machines, which would equal the rate of the machines working together. We know that there are four machines working together at the same rate, and it took them 32 hours.

So:

1/x + 1/x + 1/x + 1/x = 1/32

1/4x = 1/32

4x = 32

x = 8

Thus, the rate of the machines is 1/8.

Now we have to find the time of the order with only half of the machines working together. This time, we don't know the combined rate, so I'll substitute it for y.

1/8 + 1/8 = 1/y

1/4 = 1/y

y = 4

The time taken to complete it is 4 hours.  

3 0
3 years ago
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