QS/AC=6/60=1/10
QR/AB=QR/50=1/10
QR=5
SO THAT TRIANGLE ABC IS EQUAL TO TRIANGLE QRS(2SIDES PROPORTIONAL.INC. ANGLE)
Answer:
There is no value of x to fit this requirement.
Step-by-step explanation:
The 2 perimeters in terms of x are:
4(x + 3) for the square and
2(x+1) + 2(x +4) for the rectangle
and these need to be equal so
we equate these 2 and solve for x:
4(x + 3) = 2(x+1) + 2(x +4)
4x + 12 = 2x + 2 + 2x + 8
4x + 12 = 4x + 10
4x - 4x = 10 - 12
0 = -2 which is of course absurd so there is no solution to this equation.
Step-by-step explanation:
Slope = y2-y1 / X2-x1
= 8-4/2-(-3)
=4/5
Answer:
y = x² - 4x - 21
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (2, - 25), thus
y = a(x - 2)² - 25
To find a substitute (7, 0) into the equation
0 = a(7 - 2)² - 25 = a(5)² - 25 = 25a - 25 ( add 25 from both sides )
25a = 25 ( divide both sides by 25
a = 1, thus
y = (x - 2)² - 25 ← in vertex form
Expand and simplify
y = x² - 4x + 4 - 25
y = x² - 4x - 21 ← in standard form
Answer:
I think this will help
Step-by-step explanation:
Make a point at(-5,-6) then go up two boxes and right three boxes.
