The awnser is 7.47 you move the decimal over 4 spaces
I think the spent about an hour and 15 min on running and 45 min on jogging
Answer:
you forgot the question
Step-by-step explanation:
Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
F(x) = 5 + 2x where x is the number of times he walks the neighbours dog
y-intercept is at y=5 and slope = 2
g(x) :- As x increases by 4 g(x) decreases by -8 so the slope is -8/4 = -2
when x = 0, g(x) = the y intercept is at -1 + (-8/2) = - 5
so equation of g(x) is g(x) = -5 -2x
h(x):- the slope is (3 - 5) / (1 - 0) [ difference in y values / diff in x values]
slope = -2
so we have h(x) = -2x + c where c = the y-intercept
when x = 0 h(x) = 5
so c = 5
h(x) = 5 - 2x
Now j(x)= 2x - 5 - slope is 2 and y intercept = -5
