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igomit [66]
3 years ago
7

Please solve 1/3 ÷ 2/3​

Mathematics
1 answer:
konstantin123 [22]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

\dfrac{1}{3}\div \dfrac{2}{3}=\\\\\dfrac{1}{3}\times\dfrac{3}{2}=\\\\ \dfrac{3}{6}=\\\\\dfrac{1}{2}

Hope this helps!

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A triangle has sides of lengths 4, 3, and 5. Is it a right triangle? Explain.
vlada-n [284]

Answer:

yes; 4² + 3² = 5²

Step-by-step explanation:

Pythagorean theorem.

In a right triangle the square of the hypotenuse is equal to  the sum of the squares of the other two sides. Hypotenuse is the longest side of the triangle.

4² + 3² = 5²

16 + 9 = 25

25 = 25  

7 0
3 years ago
A tunnel is 30 yards long and 15 yards wide. The height of the tunnel walls is 5 yards before the curve of the cylinder-shaped c
Karolina [17]
The tunnel is made of two shapes and we can find the volume of each.
Cuboid volume=15×5×30=2250 cu yds.
Half cylinder volume=π(7.5)²30/2=843.75π=2649.38 cu yds.
Total volume=4899.38 cu yds.
4 0
3 years ago
Read 2 more answers
Which set contains only whole numbers divisible to 6?
melisa1 [442]
Only <span>set Y = {6, 24, 36, 78, 84}, contains only whole numbers divisible by 6.

There were no options but this was the answer to this question on a quiz.

hope this helps!</span>
7 0
3 years ago
42,300 multiply by 10 can someone show the work
Assoli18 [71]
       10
x42,300
-------------
          00
        000
     3,000
   20,000
400,000
-------------
423,000
3 0
3 years ago
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Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
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