The following graph shows a proportional relationship.

1. Flor does nails on the side. She plans to charge $ 20 a session. If each week 25 people are scheduled to get their

goldfiish [28.3K]

20 x 25 = 500 a week

4 0

2 years ago

The perimeter of a rectangular garden is 160 m and its width is 30 m. Find the cost of leveling it at the rate of $2.50 per sq.m

nalin [4]

Answer:

$12,000.

Step-by-step explanation

Length of garden = 160 m

Width of garden = 30 m

area of rectangle = length * width

substituting vale of length and width for rectangular garden we have

area of rectangular garden = 160 m * 30 M = 4800 sq. m

cost of leveling one sq. m is $2.50

and it is required to level 4800 sq. m

hence to total cost to level rectangular garden = area of rectangular garden * cost of leveling one sq. m of space

=4800 * 2.5

= 12,000

Therefore cost of leveling rectangular garden is $12,000.

5 0

2 years ago

a school is building a square shed that is 5 meters long on each side however before the construction begins school management d

nadezda [96]

It would decrease 2.5

7 0

2 years ago

A committee of 9 members is voting on a proposal. Each member casts a yea or nay vote. On a random voting basis, what is the pro

dsp73

Answer:

The required probability is $P(x)=\frac{9}{128}$ or $P(x)=0.0703125$ .

Step-by-step explanation:

Consider the provided information.

A committee of 9 members is voting on a proposal. Each member casts a yea or nay vote. On a random voting basis,

The probability of yea or nay vote is equal, = $\frac{1}{2}$

So, we can say that $p=q=\frac{1}{2}$

Use the formula: $P(x)=\binom{n}{x}p^xq^{n-x}$

Where n is the total number of trials, x is the number of successes, p is the probability of getting a success and q is the probability of failure.

We want proposal wins by a vote of 7 to 2, that means the value of x is 7.

Substitute the respective values in the above formula.

$P(x)=\binom{9}{7}(\frac{1}{2})^7(\frac{1}{2})^{9-7}$

$P(x)=\frac{9!}{7!2!}(\frac{1}{2})^7(\frac{1}{2})^{2}$

$P(x)=\frac{8\times9}{2}\times(\frac{1}{2})^9$

$P(x)=\frac{4\times9}{2^9}$

$P(x)=\frac{9}{2^7}$

$P(x)=\frac{9}{128}$ or $P(x)=0.0703125$

Hence, the required probability is $P(x)=\frac{9}{128}$ or $P(x)=0.0703125$ .

4 0

3 years ago

19-42 evaluate the integral.<br> 23. <img src="https://tex.z-dn.net/?f=%5Cint_%7B0%7D%5E%7B2%7D%282%20x-3%29%5Cleft%284%20x%5E%7

34kurt

Expand the integrand:

$(2x - 3) (4x^2 + 1) = 8x^3 - 12x^2 + 2x - 3$

Then integrate using the power rule:

$\displaystyle \int (8x^3-12x^2+2x-3) \, dx = 2x^4 - 4x^3 + x^2 - 3x + C$

By the fundamental theorem of calculus, the definite integral has a value of

$\displaystyle \int_0^2 (2x-3)(4x^2+1) \, dx = \left(2x^4 - 4x^3 + x^2 - 3x\right)\bigg|_{x=2} - \left(2x^4 - 4x^3 + x^2 - 3x\right)\bigg|_{x=0}$

$\displaystyle \int_0^2 (2x-3)(4x^2+1) \, dx = 32 - 32 + 4 - 6 = \boxed{-2}$

3 0

2 years ago