The 3rd slot is the answer you are looking for
The largest possible volume of the given box is; 96.28 ft³
<h3>How to maximize volume of a box?</h3>
Let b be the length and the width of the base (length and width are the same since the base is square).
Let h be the height of the box.
The surface area of the box is;
S = b² + 4bh
We are given S = 100 ft². Thus;
b² + 4bh = 100
h = (100 - b²)/4b
Volume of the box in terms of b will be;
V(b) = b²h = b² * (100 - b²)/4b
V(b) = 25b - b³/4
The volume is maximum when dV/db = 0. Thus;
dV/db = 25 - 3b²/4
25 - 3b²/4 = 0
√(100/3) = b
b = 5.77 ft
Thus;
h = (100 - (√(100/3)²)/4(5.77)
h = 2.8885 ft
Thus;
Largest volume = [√(100/3)]² * 2.8885
Largest Volume = 96.28 ft³
Read more about Maximizing Volume at; brainly.com/question/1869299
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Answer:
D) y = 1/4 x^2
Step-by-step explanation:
For these functions, the leading coefficient can be considered to be either ...
the vertical scale factor (larger ⇒ narrower)
the square of the inverse of the horizontal scale factor.
In the latter case, the horizontal scale factor will be larger (wider) when its inverse and the square of its inverse are smaller.
Either way, you're looking for the smallest leading coefficient: 1/4.
Answer:
Volume = 52.5
Step-by-step explanation:
volume of a rectangular 3d shape can be calculated by length*width*height. In this case:
7*10*0.75 = 52.5
Answer:
simple. y=x+2
Step-by-step explanation:
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