Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
it would be -4.5
Step-by-step explanation:
cause thats the middle
Answer:
55/28 hours/day (approx. 1.96 hours/day)
Step-by-step explanation:
9 1/6 hours / 4 2/3 days
= 55/6 hours / 14/3 days
= 55/6 * 3/14 hours/day
= 55/28 hours/day
(approx. 1.96 hours/day)
We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

Where:

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

Now we substitute the values:

Now we solve the operations, we get:

Therefore, the present value must be $39462.50