Let the width be x.
Length is 8 feet more than width. Length = x + 8
Area = x(x + 8)
width increased by 4, that is, (x + 4)
Length decreased by 5, (x + 8 - 5) = (x + 3)
Area = (x + 4)(x +3)
Area remains the same
x(x + 8) = (x+4)(x +3)
x² + 8x = x(x +3) + 4(x +3)
x² + 8x = x² +3x + 4x +12
x² + 8x = x² +7x +12 Eliminate x² from both sides
8x = 7x + 12
8x - 7x = 12
x = 12
Dimensions of original rectangle : x, x + 8
12, 12 +8 = 12, 20
Original rectangle is 20 feet by 12 feet
The given equality hold true when x = 2.
Put x = 2 in inequality.
2(2) + 3 = 4+3 = 7 = R.H.S.
For x = 4 and 6, L.H.S(2x+3) is greater than 7.
Hence for x = 2, 4 and 6, the above inequality holds true.
Hope this helps!
Using the points (0,14) and (10,0), the gradient of the line is (14-0)/(0-5) which simplifies to -7/5.
From these points, we can also see that when the x value is zero, the y value is 14. Therefore the y-intercept is 14.
We can then put this into the equation of a straight line, y=mx+c:
y = (-7/5)x + 14
Answer:
Step-by-step explanation:
A = h(a+b)/2 for h
2A = h(a + b)
h(a+b) = 2A
h = 2A/(a+b)
