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icang [17]
3 years ago
6

40 POINTS PLEASE HELP

Mathematics
1 answer:
kogti [31]3 years ago
7 0
You’re gonna use the midpoint formula to find the radius: (1+7/2, 2-6/2) and get (4,-2). Now you use the distance formula to find the radius which would be √(1-4)^2 + (2-(-2)^2 and get 5 (√= square root of). Now you plug that into the circumference equation C= 2 x pi x 5 and get 31.4 units. Sorry that took me so long and hope this helps you out!!
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If 100 cats kill 100 mice in 100 days, then 4 cats would kill 4 mice in how many days ?
Gemiola [76]
If 100 cats killed 100 mice in 100 days, you can say that each cat killed one mouse the day after the last cat. So, if four cats killed four mice, and we're going of off the same basis that each cat killed one mouse the day after the last cat, then the answer would be 4.
4 0
3 years ago
Find the area of this circle.<br> Use 3.14 to approximate<br> A = ar2<br> 20 ft
trasher [3.6K]

Answer:

314

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
3 years ago
The equation y = 10x shows how the
lubasha [3.4K]
$80.00 hope this helps!
4 0
3 years ago
Which axiom is used to prove that the product of two rational numbers is rational
aliina [53]

Answer:

First, a rational number is defined as the quotient between two integer numbers, such that:

N = a/b

where a and b are integers.

Now, the axiom that we need to use is:

"The integers are closed under the multiplication".

this says that if we have two integers, x and y, their product is also an integer:

if x, y ∈ Z ⇒ x*y ∈ Z

So, if now we have two rational numbers:

a/b and c/d

where a, b, c, and d ∈ Z

then the product of those two can be written as:

(a/b)*(c/d) = (a*c)/(b*d)

And by the previous axiom, we know that a*c is an integer and b*d is also an integer, then:

(a*c)/(b*d)

is the quotient between two integers, then this is a rational number.

5 0
3 years ago
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