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SpyIntel [72]
3 years ago
6

A candy company plans to hang posters of a new product in supermarkets. The product is a box of premium chocolates. The art team

made a scale drawing of the top of the box using a scale of 3 inches to 1 inch. The length of the scale drawing of the box is 24 inches, and its width is 15 inches. What are the actual dimensions of the top of the chocolate box?
A.) The length is 8 inches, and the width is 5 inches.

B.) The length is 12 inches, and the width is 7.5 inches.

C.) The length is 16 inches, and the width is 10 inches.

D.) The length is 22 inches, and the width is 12 inches.
Mathematics
2 answers:
SashulF [63]3 years ago
8 0
<span>B.) The length is 12 inches, and the width is 7.5 inches</span>
Sloan [31]3 years ago
7 0

Answer:

A) The length is 8 inches, and the width is 5 inches.

Step-by-step explanation:

Given,

The scale in the drawing is,

3 inches to 1 inches,

That is, for 1 inches of measure, the measure of the drawing is 3 inches,

Thus, the original measures of the box will obtained after dividing each measures of the drawing by 3,

Here, the length of the scale drawing of the box is 24 inches and its width is 15 inches,

So, the length of the box = \frac{24}{3} = 8 inches,

And, the width of je box = \frac{15}{3} = 5 inches,

Hence, Option 'A' is correct.

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3 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

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4 0
3 years ago
Frozen motts sticks cost $.022 each. If there are 6 sticks in on order, what is the portion cost for an order of motts sticks?
solong [7]

Answer:

$ 1.32

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

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Now there are 6 sticks in an order . So the cost of six sticks will be ,

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8 0
3 years ago
Please help me I suck at math!​
lisov135 [29]

Answer:

<em>0.000008</em>

Step-by-step explanation:

Since the exponent of the scientific notation is negative, move the decimal point  6  places to the left.

<em>0.000008</em>

<em>brainliest pls</em>

8 0
3 years ago
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A couple deposits $23,000 earning 3% annual intrest for 30 years. calculthe future value of the investment of the intrest is com
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A = 23,000(1 + .03/365)^365(30)
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