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3 years ago

PLZ HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

notsponge [240]3 years ago

6 0

Answer:

$72 would be the retail price

Step-by-step explanation:

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4/5 ÷ 7/6 + 2/7 ∙2 1/5

Aleksandr [31]

<h2>The value of $\dfrac{4}{5}$ ÷ $\dfrac{7}{6}$ + $\dfrac{2}{7}.2\dfrac{1}{5}$ $=\dfrac{8}{7}$ </h2>

Step-by-step explanation:

We have,

$\dfrac{4}{5}$ ÷ $\dfrac{7}{6}$ + $\dfrac{2}{7}.2\dfrac{1}{5}$

To find, the value of $\dfrac{4}{5}$ ÷ $\dfrac{7}{6}$ + $\dfrac{2}{7}.2\dfrac{1}{5}$ = ?

∴ $\dfrac{4}{5}$ ÷ $\dfrac{7}{6}$ + $\dfrac{2}{7}.2\dfrac{1}{5}$

$=\dfrac{4}{5}\times \dfrac{6}{7} +\dfrac{2}{7}.\dfrac{8}{5}$

$=\dfrac{24}{35} +\dfrac{16}{35}$

Taking LCM of denominator, we get

$=\dfrac{24+16}{35}$

$=\dfrac{40}{35}$

Dividing numerator and denominator by 5, we get

$=\dfrac{8}{7}$

∴ The value of $\dfrac{4}{5}$ ÷ $\dfrac{7}{6}$ + $\dfrac{2}{7}.2\dfrac{1}{5}$ $=\dfrac{8}{7}$

Hence, the value of $\dfrac{4}{5}$ ÷ $\dfrac{7}{6}$ + $\dfrac{2}{7}.2\dfrac{1}{5}$ is equal to $\dfrac{8}{7} .$

4 0

3 years ago

Type the correct answer in each box. The reflection of point S across the y-axis is point . The reflection of point Q across the

tresset_1 [31]

Answer:

$S' = (-5,-5)$

$Q"=(-5,-5)$

Step-by-step explanation:

Given

$S = (5,-5)$

$Q= (5,5)$

Solving (a): Reflect S across y-axis

The rule to reflect across y-axis is:

$(x,y) \to (-x,y)$

So, we have:

$S(5,-5) \to S'(-5,-5)$

Hence:

$S' = (-5,-5)$

Solving (b): Reflect Q across x and y-axis

The rule to reflect across x-axis is:

$(x,y) \to (x,-y)$

So:

$Q(5,5) \to Q'(5,-5)$

The rule to reflect across y-axis is:

$(x,y) \to (-x,y)$

So:

$Q'(5,-5) \to Q"(-5,-5)$

Hence:

$Q"=(-5,-5)$

6 0

3 years ago

The angle looking up at the sun is 70°. A flagpole casts a shadow of 15 ft. Draw a diagram and find the height of the flagpole

dangina [55]

Answer:

The length of the flagpole be 41.2 ft .

Option (A) is correct .

Step-by-step explanation:

As given

The angle looking up at the sun is 70°.

A flagpole casts a shadow of 15 ft .

Now by using the trignometric identity .

$tan \theta = \frac{Perpendicular}{Base}$

$\ theta = 70^{\circ}$

$tan\ 70^{\circ} = \frac{AB}{BC}$

BC = 15 ft

tan 70° = 2.75 (Approx)

$2.75 = \frac{AB}{15}$

AB = 2.75 × 15

= 41.2 ft

Therefore the length of the flagpole be 41.2 ft .

Option (A) is correct .

5 0

2 years ago

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Jack knows the surface area of a cylinder and its radius. He wants to find the cylinder's height. He needs to rewrite the formul

Sindrei [870]

This formula should help you.

4 0

2 years ago

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b> Find the equation to the straight lines passing through (1,1) and parallel to the lines represented by x²-5xy+4y²+x+2y-2=0

olasank [31]

please mark brainlist...

4 0

2 years ago