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Olenka [21]
3 years ago
9

A bedroom is in the shape of a rectangle. The length of the bedroom is represented by 3x^2 and the width is represented by 7x+14

. The square rug has a length of 4x +3 what is the area of the bedroom that is not covered by the rug?
PLEASE HELP
Mathematics
1 answer:
pentagon [3]3 years ago
6 0

The area of the room that is not covered by the rug is: 21x^3+26x^2-24x+9

Step-by-step explanation:

Let L be the length of the room

and

W be the width of the room

Then

L = 3x^2

W = 7x+14

Area of the bedroom:

A_r = L*W\\=3x^2(7x+14)\\=21x^3+42x^2

Area of Rug:

Let S be the side of rug

S = 4x+3

A_{rug} =S^2\\=(4x+3)^2\\=(4x)^2+2(4x)(3)+(3)^2\\=16x^2+24x+9

The area of the room that is not covered by the rug will be obtained by subtracting the area of the rug from the area of the room.

So,

Area\ of\ room\ not\ covered\ by\ rug =A_r - A_{rug}\\= 21x^3+42x^2-(16x^2+24x+9)\\=21x^3+42x^2-16x^2-24x-9\\=21x^3+26x^2-24x+9

Hence,

The area of the room that is not covered by the rug is: 21x^3+26x^2-24x+9

Keywords: Rectangle, square

Learn more about area at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

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cupoosta [38]

Answer:

The equivalent expression \frac{8^4}{7^4} = \frac{4096}{2401}\approx 1.71

Step-by-step explanation:

Given:

(\frac{8}{7})^4

We need to find the equivalent for given expression.

Solution:

(\frac{8}{7})^4

Now by using Law of indices which states;

(\frac{a}{b})^n= \frac{a^n}{b^n}

So applying the same in given expression we get;

\frac{8^4}{7^4}

Now we can say that;

8^4 = 8 \times 8 \times 8 \times 8

Also

7^4 = 7 \times 7 \times 7 \times 7

\frac{8^4}{7^4} = \frac{8 \times 8 \times 8 \times 8}{7 \times 7 \times 7 \times 7}

Now We know that;

8 \times 8 \times 8 \times 8 = 4096

7 \times 7 \times 7 \times 7 = 2401

On substituting we get;

\frac{8^4}{7^4} = \frac{4096}{2401}\approx 1.71

Hence The equivalent expression \frac{8^4}{7^4} = \frac{4096}{2401}\approx 1.71

5 0
3 years ago
Please help on this question asap
Stels [109]
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I hope this helped Lul
7 0
2 years ago
Simplify the expression.
notsponge [240]
The answer is 2k^2 - 7k - 4 because 2k x k is 2k^2 and 2k x (-4) is -8k and 1 x k is k and 1 x (-4) is -4. So then you would get 2k^2 - 8k + k - 4 which simplifies to 2k^2 - 7k - 4 which is your answer.
8 0
3 years ago
Pls can someone help me and have it right
dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

18\times3=54

A division equation to hold the table true:

\frac{54}{3} =18

Step-by-step explanation:

Given in problem 1:

(a). The equation is \frac{x}{6} > 1

It holds true for all values of x> 6.

Let us say x=12,

\frac{x}{6}=\frac{12}{6}  =2 which is greater than 1.

(b). The equation is \frac{x}{6} < 1

It holds true for all values of x< 6.

Let us say x=3

\frac{x}{6} =\frac{3}{6} =\frac{1}{2} which is less than 1.

(c). The equation is \frac{x}{6} = 1

It holds true for only x= 6.

Let us say x=6,

\frac{x}{6} =\frac{6}{6}=1 which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

18\times3=54

A division equation to hold the table true:

\frac{54}{3} =18

Therefore these are the values which hold true to the equation in problem 1 and 2.

8 0
3 years ago
Find m∠1 if m∠2=73°, m∠3=107°, m∠4=92°. Justify your response!
a_sh-v [17]

Answer:

m∠1 = 92°

Step-by-step explanation:

∠2 corresponds to the supplement of ∠3 if (and only if) lines a and b are parallel. We find that

m∠2 + m∠3 = 73° +107° = 180°

so, the angles are supplementary and lines a and b are parallel.

Angles 4 and 1 are corresponding angles where the line d crosses the parallel lines a and b, so are congruent.

m∠1 = m∠4 = 92°

7 0
2 years ago
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