What's the vertex form of the function?

I need an answer for the empty spaces

abruzzese [7]

Answer:

4, +, 6

Step-by-step explanation:

3 0

3 years ago

And can you please explain what does SAS-AA-ASA-SSS mean

Jet001 [13]

This is how a triangle is equal to one another, SAS is side angle side, AA is angle angle, ASA is angle side angle, and SSS is side side side, yours looks like AA but I might be wrong. I believe it is AA, so if you have no clue just go with AA

5 0

3 years ago

Read 2 more answers

The current balance of Amber’s bank account was $8. She withdrew

8_murik_8 [283]

Answer:

$-6

Step-by-step explanation:

$(8-14)

= $-6

Hope this helped!

4 0

3 years ago

Read 2 more answers

Ed plants trees in city parks. He used 1\10 of a bag of fertilizer around the base of a newly planted tree. How many trees can E

valina [46]

To determine this you could think of it in a couple ways.

1. If it takes 1/10 of a bag of fertilizer to put around 1 tree, he can fertilize 10 trees with 1 bag because there are 10 groups of 1/10 in a bag. Take 10 x 40 because there are 40 bags and get 400 trees to be fertilized.

2. You can divide 40 by 1/10 as the other strategy.
This is the same as 40 x 10/1.

Also equaling 400 trees that can be fertilized.

4 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$