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Marysya12 [62]
3 years ago
7

When two or more waves are at the same place at the same time, the resulting effect is calleda. a standing wave.b. a Doppler wav

e.c. a shock wave.d. interference.e. a period
Physics
2 answers:
mr_godi [17]3 years ago
7 0

Answer:

The correct option is;

d. interference

Explanation:

Interference is the result of the superposition of waves.

Superposition of waves occurs when two or more waves are present at a point.

When we superimpose two or more waves are at the same place at the same time, the resulting amplitude is the sum of the amplitude of the individual waves, resulting in a similar wave with a larger amplitude.

Where we have the resultant of the superposition wave have a larger amplitude than any of the included individual wave, it is termed constructive interference

However, when the amplitude of the resultant superposition wave due to the sum of two or more waves is less than than any of the included wave, or zero, we have destructive interference.

IgorLugansk [536]3 years ago
6 0

Answer: option D

Explanation: The combination of 2 waves to produce a resultant effect at a point is known as interference.

If the waves are in the same direction, the resultant effect is of a larger magnitude, this is called constructive interference which is still a progressive wave.

If the resultant effect brings about cancellation of both waves, we have a destructive interference which forms a standing wave.

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3 years ago
A 2000-kg sailboat experiences an eastward force of 2000 N by the ocean tide and a wind force against its sails with magnitude o
BaLLatris [955]

Answer:

The force exerted by the ocean tide is directed to the right (east).

The force exerted by the wind is directed to the northwest (45° N of W).

We should separate the x- and y- components of the wind force, and evaluate each component separately.

F_x = 6000\cos(\pi/4)(-\^{x})\\F_y = 6000\sin(\pi/4)(+\^{y})

We denote the direction to the right as the positive direction, so the x-component of the wind force is in the negative direction.

The resultant force is as follows:

F_R = [2000 - 4242.64](\^{x}) + [4242.64](\^{y})\\F_R = -2242.64\^{x} + 4242.64\^{y}

The resultant acceleration can be found by Newton's Second Law:

F = ma\\\\a_R = F_R/m = -1.12\^{x} + 2.12\^{y}

The magnitude of the resultant acceleration is

|a_R| = \sqrt{(1.12)^2 + (2.12)^2} = 2.4 ~m/s^2

7 0
3 years ago
The construction of a flat rectangular roof (6.17 m × 5.92 m) allows it to withstand a maximum net outward force of 2.00 × 104 N
Blababa [14]

Answer:

v_2=29.13\ m/s

Explanation:

It is given that,

Dimension of the rectangular roof, (6.17 m × 5.92 m)

The maximum net outward force, F=2\times 10^4\ N

The density of air, \rho=1.29\ kg/m^3

The Bernoulli equation is used to find wind speed of this roof blow outward. It is given by :

P_1+\dfrac{1}{2}\rho v_1^2=P_2+\dfrac{1}{2}\rho v_2^2

Here, v_1=0 (since air inside the roof is not moving)

v_2=\sqrt{\dfrac{2(P_1-P_2)}{\rho}}

Since, F=(P_1-P_2)A

v_2=\sqrt{\dfrac{2F}{\rho A}}

v_2=\sqrt{\dfrac{2\times 2\times 10^4}{1.29\times 6.17\times 5.92 }}

v_2=29.13\ m/s

So, the wind speed of  this roof blow outward is 29.13 m/s. Hence, this is the required solution.

5 0
4 years ago
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