1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STatiana [176]
3 years ago
13

a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i

s the net force on the runner? c.) how far does the sprinter travel during the 3 s?
Physics
1 answer:
Katyanochek1 [597]3 years ago
3 0
Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
             a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time

Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
               F = m x a
where F is force,
m is mass, and 
a is acceleration

Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
The distance that the sprinter travel is calculated through the equation,
         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
             d = 13.5 m

<em>ANSWER: d = 13.5 m</em>

You might be interested in
Students have a small steel ball and a large steel ball, and they have a short ramp and a tall ramp.
lozanna [386]
I would say it’s “B” for the reason that the student did not experiment with a short ramp and large ball as well as a large ramp and a short ball. They have to do those experiments as well before drawing their conclusion.
3 0
1 year ago
Read 2 more answers
The classical pathway for complement activation is initiated by
maks197457 [2]

Answer: The classical complement pathway for complement activation is initiated by antigen-antibody complexes with the antibody isotypes IgG and IgM.

Explanation: The classical complement pathway typically requires antigen-antibody complexes (immune complexes) for activation (specific immune response), whereas the alternative pathway can be activated by C3 hydrolysis, foreign material, pathogens, or damaged cells.

After activation, a series of proteins are recruited to generate C3 convertase, which cleaves the C3 protein. The C3b component of the cleaved C3 binds to C3 convertase to generate C5 convertase, which cleaves the C5 protein. The cleaved products attract phagocytes to the site of infection and tags target cells for elimination by phagocytosis. In addition, the C5 convertase initiates the terminal phase of the complement system, leading to make appear the membrane attack complex. The membrane attack complex creates a pore on the target cell's membrane, inducing cell lysis and death.

4 0
3 years ago
Gravity affects atmospheric pressure true or false
Burka [1]

Answer:

false

Explanation:

5 0
3 years ago
Two runners start at the same point on a straight track. The first runs with constant acceleration so that he covers 98 yards in
charle [14.2K]

Answer:

94.13 ft/s

Explanation:

<u>Given:</u>

  • t = time interval in which the rock hits the opponent = 10 s - 5 s = 5 s
  • s = distance to be moved by the rock long the horizontal = 98 yards
  • y = displacement to be moved by the rock during the time of flight along the vertical = 0 yard

<u>Assume:</u>

  • u = magnitude of initial velocity of the rock
  • \theta = angle of the initial velocity with the horizontal.

For the motion of the rock along the vertical during the time of flight, the rock has a constant acceleration in the vertically downward direction.

\therefore y = u\sin \theta t +\dfrac{1}{2}(-g)t^2\\\Rightarrow 0 = u\sin \theta 5 +\dfrac{1}{2}(-9.8)\times 5^2\\\Rightarrow u\sin \theta 5 =\dfrac{1}{2}(9.8)\times 5^2......(1)\\

Now the rock has zero acceleration along the horizontal. This means it has a constant velocity along the horizontal during the time of flight.

\therefore u\cos \theta t = s\\\Rightarrow u\cos \theta 5 = 98.....(2)\\

On dividing equation (1) by (2), we have

\tan \theta = \dfrac{25}{20}\\\Rightarrow \tan \theta = 1.25\\\Rightarrow \theta = \tan^{-1}1.25\\\Rightarrow \theta = 51.34^\circ

Now, putting this value in equation (2), we have

u\cos 51.34^\circ\times  5 = 98\\\Rightarrow u = \dfrac{98}{5\cos 51.34^\circ}\\\Rightarrow u =31.38\ yard/s\\\Rightarrow u =31.38\times 3\ ft/s\\\Rightarrow u =94.13\ ft/s

Hence, the initial velocity of the rock must a magnitude of 94.13 ft/s to hit the opponent exactly at 98 yards.

3 0
3 years ago
What do you notice from the picture?​
Schach [20]
Answer:there talking about the house
5 0
3 years ago
Read 2 more answers
Other questions:
  • A student is given a red and a blue liquid. The two samples of liquids are heated in identical beakers over identical Bunsen bur
    10·2 answers
  • For a molecule of O2 at room temperature (300 K), calculate the average angular velocity for rotations about the x or y axes. Th
    11·1 answer
  • The coefficient of static friction between Teflon and scrambled eggs is about 0.04. What is the smallest angle from the horizont
    12·1 answer
  • -Gravity is affected by the:
    10·2 answers
  • 3.
    8·2 answers
  • Basking in the sun, a 1.10 kg lizard lies on a flat rock tilted at an angle of 15.0° with respect to the horizontal. What is the
    13·1 answer
  • A car with a mass of 1140 kg is traveling in a mountainous area with a constant speed of 71.8 km/h. The road is horizontal and f
    10·1 answer
  • The rotation period for Venus is___days. (pls help!)<br> 365<br> 186<br> 512<br> 243
    11·2 answers
  • Please round to three sig fig
    8·1 answer
  • Show by dimension that the equation of motion is correct <br>V² = U²+2as​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!