Answer:
Option D
0.83 m/s2
Explanation:
Time is assumed as 10 seconds
First, convert the speeds from km/h to m/s
20 km/h\times \frac {1000 m}{3600 s}=5.555555556 m/s
\approx 5.56 m/s
50 km/h\times \frac {1000 m}{3600 s}=13.88888889 m/s \approx 13.89 m/s
Acceleration, where u and v are the initial and final velocities respectively, t is the time taken to accelerate.
Substituting 13.89 m/s for v, 5.56 m/s for u and 10 s for t then
Red areas correspond to 25 to 35 centimeters above normal.
So answer is C.
S= 1/2 x 182 x t = 1688.3
t = 1688.3 / 91
time = 18.55 seconds
Answer:
No, they are not because when you stretch the rubber band you are deforming it but with the spring it is made to go up and down.
Explanation:
I am pretty sure that<span> the following which describes resistance force is the fourth option from the scale represented above : </span>D .force applied by the machine to overcome resistance. I choose this due to the Newton's 3rd law, as the<span> force that shoul be overcome by a machine before it perform its usual work. Do hope you will find it helpful! Regards!</span>