Answer
given,
length of the track = 200 m
speed of runner 1 = 6.20 m/s
speed of the runner 2 = 5.5 m/s
distance covered by the fastest runner, d = 6.2 t
distance covered by the slow runner,d = 5.50 t + 200
time taken to overtake for the first time
6.2 t = 5.50 t + 200
0.7 t = 200
t = 285.7 s
distance covered from the starting point
d = 6.2 t
d = 6.2 x 285.7
d = 1771.43 m
for next overtaking time taken will be double
t' = 258.7 x 2 = 571.4 s
distance travel by the runner from the starting point
d' = 6.2 t'
d' = 6.2 x 571.4
d' = 3542.68 m
I’m 95% sure it’s covalent bonds.
Answer:
Shorter than(?)
Explanation:
What is it that you're looking for here? Is it just some random fill in the blank question?
My guess is that the horizontal distance has to be shorter than that of the ladder length because if it wasn't then the ladder would be laying down or maybe standing straight up... and you can't really use it normally like that... I'm sorry, where is the Physics in this question exactly?
To solve the problem it is necessary to apply the concepts related to Kepler's third law as well as the calculation of distances in orbits with eccentricities.
Kepler's third law tells us that
Where
T= Period
G= Gravitational constant
M = Mass of the sun
a= The semimajor axis of the comet's orbit
The period in years would be given by
PART A) Replacing the values to find a, we have
Therefore the semimajor axis is 
PART B) If the semi-major axis a and the eccentricity e of an orbit are known, then the periapsis and apoapsis distances can be calculated by
