N+d=34
.05n+.10d=2.60
Solve by substitution
n=34-d
.05(34-d)+.10d=2.60
1.7-.05d+.10d=2.60
.05d=.90
d=18 dimes
18+n=34
n=16 nickles
The binomial factors of the quadratic trinomial may take the forms of (y + a) and (y + b). The sum of a and b is equal to the numerical coefficient of the second term and their product should be equal to the constant. If a is equal to -2, b is equal to -8. Thus, the second factor is (y - 8).
Answer:
+1/7
Step-by-step explanation:
One approach to evaluating this would be to rewrite it as:
-2 -5
------ * --------- .
10 7 This reduces to:
2
--------- = +1/7
2(7)
4x -3y + z = -10...............(1)
2x +y + 3z = 0...............(2)
-x +2y - 5z = 17...............(3)
First we multiply 3*(2) and add it to (1)
6x +3y +9z =0..................+(1)..................> 10x + 10z = -10......(4)
Then we multiply -2*(2) and add it to (3)
-4x -2y -6z =0 ...................+(3)................> -5x -11z = 17...........(5)
Multiply 2*(5) and add it to (4)
-10x -22z = 34...................+(4).................> -12 z = 24 ..............>>> z = -2
Substitute z in (4)............> 10x +10(-2) = -10.............................>>> x = 1
Substitute x and z in (2).....> 2(1) +y + 3(-2) = 0..................>>> y = 4
Solution (x,y,z) = (1,4,-2)
Answer: (1, 3)
Explanation:
2x + 4x - 1 = 5
6x = 6
x = 1
y = 4(1) - 1
y = 4 - 1
y = 3