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2 years ago

For which interval is the function increasing Choose two answers that are correct

Mathematics

1 answer:

kaheart [24]2 years ago

3 0

Answer:

-8 ≤ x ≤ - 6

2 ≤ x ≤ 6

Step-by-step explanation:

Increasing part of the function can be easily determined from the graph.

Note that increasing function means for each successive values of 'x', the values of 'y' keep increasing.

From the graph, we see that the function is increasing in the interval $- 8 \leq \ x \leq -6$

Between -6 and -4, the graph is constant and takes the value 4.

After that it decreases till x = -2 until it becomes a constant function again on x = 2.

Then, it again increases from x = 2 till x = 6. This is represented by the interval

$2 \leq x \leq 6$ .

Then it again decreases.

So, OPTION A and C are the answers.

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PLEASE HELP For the expression below, write two other equivalent expressions using different terms. Make sure one is fully simpl

Julli [10]

Given:

The given expression is

$-4(x+2)-2x+4$

To find:

The two other equivalent expressions.

Solution:

We have,

$-4(x+2)-2x+4$

Using distributive property, we get

$=-4(x)-4(2)-2x+4$

$=-4x-8-2x+4$

So, one equivalent expression is $-4x-8-2x+4$ .

On further simplification, we get

$=(-4x-2x)+(-8+4)$

$=6x-4$

Therefore, the second and fully simplified equivalent expression is $6x-4$ .

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3 years ago

What Fraction Is Equivalent to 3/9

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3 years ago

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Marat540 [252]

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3 years ago

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given the function f(x)=x^3 +x^2-2x+1 what is the resulting function f(x) is shifted to the left one unit

Nadya [2.5K]

Answer:

The resulting function is $f(x+1) = x^3 + 4x^2 + 3x + 1$

Step-by-step explanation:

Suppose we have a function f(x). If we want to shift the function 1 unit to the left, we find f(x+1).

In this question, we have:

$f(x) = x^3 + x^2 - 2x + 1$

Shifting 1 unit to the left:

$f(x+1) = (x+1)^3 + (x+1)^2 - 2(x+1) + 1$

$f(x+1) = (x^3 + 3x^2 + 3x + 1) + (x^2 + 2x + 1) - 2x - 2 + 1$

$f(x+1) = x^3 + (3+1)x^2 + (3+2-2)x + 1 + 1 - 2 + 1$

$f(x+1) = x^3 + 4x^2 + 3x + 1$

The resulting function is $f(x+1) = x^3 + 4x^2 + 3x + 1$

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2 years ago

For the given quadratic equation convert into vertex form, find the vertex and find the value for x=6 Y=-2x^2+2x+2

Serga [27]

Answer:

Part 1) The vertex is the point (0.50,2.50)

part 2) $y=-58$

Step-by-step explanation:

we have

$y=-2x^{2} +2x+2$

Part 1) Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2=-2x^{2} +2x$

Factor the leading coefficient

$y-2=-2(x^{2} -x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-2-0.50=-2(x^{2} -x+0.25)$

$y-2.50=-2(x^{2} -x+0.25)$

$y-2.50=-2(x-0.50)^{2}$

$y=-2(x-0.50)^{2}+2.50$ -----> equation in vertex form

The vertex is the point (0.50,2.50)

Part 2) Find the value of y for x=6

substitute the value of x in the equation

$y=-2(6)^{2} +2(6)+2$

$y=-72 +12+2$

$y=-58$

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3 years ago