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morpeh [17]
3 years ago
5

The diameter of the pan is 9 inches. What is the approximate circumference of a lid that will fit his frying pan? (Use 3.14 for

.)
A.
56.52 in
B.
14.13 in
C.
28.26 in
D.
254.34 in
Mathematics
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

28.26

Step-by-step explanation:

the equation for circumference is 2pi*r or pi*d

3.14*9 (the diametre) is 28.26

Answer 28.26

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Answer:

Rewrite this question

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3 years ago
Choose the best description for the real number 35
Natalija [7]

Answer:

A) Irrational, because it is not a terminating or repeating decimal.

Step-by-step explanation:

Every time a square root results in a decimal, it will always never end, and never repeat. The square root of 35 qualifies for both of these qualities, therefore, making the answer (A). Hope this helps!

5 0
3 years ago
ILL GIVE BRAINELST
murzikaleks [220]

Answer:

A = 12 ft

Step-by-step explanation:

Perimeter ( of SQUARE) B = 64

  then each side = 64/4 = 16

AREA of SQUARE C = 400

    side X side = 400

        then side = sqrt 400

Now use Pyhtagorean Theorem to find leg of right triangle that is

   side A  Side B  hypotenuse Side C

A^2 + 16^2 = (sqrt 400)^2

A^2 = 400 - 256

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6 0
2 years ago
Explain why the lines are parallel given the angles shown. Assume that all tile patterns use this basic shape.
avanturin [10]

The 3rd one: "Converse of the Same-Side Interior Angles Postulate"

7 0
3 years ago
Does anyone know the answers to these?
dem82 [27]

Step-by-step explanation:

a. The point estimate is the mean, 47 days.

b. The margin of error is the critical value times the standard error.

At 31 degrees of freedom and 98% confidence, t = 2.453.

The margin of error is therefore:

MoE = 2.453 × 10.2 / √32

MoE = 4.42

c.  The confidence interval is:

CI = 47 ± 4.42

CI = (42.58, 51.42)

d. We can conclude with 98% confidence that the true mean is between 42.58 days and 51.42 days.

e. We can reduce the margin of error by either increasing the sample size, or using a lower confidence level.

3 0
3 years ago
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