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victus00 [196]
3 years ago
8

For the given quadratic equation convert into vertex form, find the vertex and find the value for x=6 Y=-2x^2+2x+2

Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

Part 1) The vertex is the point (0.50,2.50)

part 2) y=-58

Step-by-step explanation:

we have

y=-2x^{2} +2x+2

Part 1) Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-2=-2x^{2} +2x

Factor the leading coefficient

y-2=-2(x^{2} -x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-2-0.50=-2(x^{2} -x+0.25)

y-2.50=-2(x^{2} -x+0.25)

y-2.50=-2(x-0.50)^{2}

y=-2(x-0.50)^{2}+2.50 -----> equation in vertex form

The vertex is the point (0.50,2.50)

Part 2) Find the value of y for x=6

substitute the value of x in the equation

y=-2(6)^{2} +2(6)+2

y=-72 +12+2

y=-58

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2 years ago
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Answer:

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3 years ago
( BRAINLIEST QUEATION)
mr Goodwill [35]

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2 years ago
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3 0
3 years ago
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Viefleur [7K]
294.000 is your answer
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