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jeka94
2 years ago
9

Which statements are true about these lines? Select three options.

Mathematics
1 answer:
gayaneshka [121]2 years ago
6 0

i need the ancwer options and the linea

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There is a set of 12 cards numbered 1 to 12. A card is chosen at random. Event A is choosing a number less
kaheart [24]

The number of permutations of picking 4 pens from the box is 30.

There are six different unique colored pens in a box.

We have to select four pens from the different unique colored pens.

We have to find in how many different orders the four pens can be selected.

<h3>What is a permutation?</h3>

A permutation is the number of different arrangements of a set of items in a particular definite order.

The formula used for permutation of n items for r selection is:

    ^nP_r = \frac{n!}{r!}

Where n! = n(n-1)(n-2)(n-3)..........1 and r! = r(r-1)(r-2)(r-3)........1

We have,

Number of colored pens = 6

n = 6.

Number of pens to be selected = 4

r = 4

Applying the permutation formula.

We get,

= ^6P_4

= 6! / 4!

=(6x5x4x3x2x1 ) / ( 4x3x2x1)

= 6x5

=30

Thus the number of permutations of picking  4 pens from a total of 6 unique colored pens in the box is 30.

Learn more about permutation here:

brainly.com/question/14767366

#SPJ1

6 0
1 year ago
Which of the following is the probabilty against drawing a heart from a standard deck of 52 cards?
nevsk [136]
 <span>p = 39/52 = 3/4 = 0.75
</span>
13 cards each of 4 different suits
if you draw a card, there are 39 cards that
are not hearts out of 52 all together.
3 0
3 years ago
mr. duc asked perry to set up 450 chairs in a large hall. perry puts 20 chairs in each row. he has already set up 15 rows of cha
Brums [2.3K]
The number of chairs that still  need to be set up are 150.
6 0
3 years ago
Read 2 more answers
Hellpppppppppppp...<br> '
Mars2501 [29]

Answer:

1 1/2

one and one half.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
To assess the accuracy of a laboratory scale, a standard weight that is known to weigh 1 gram is repeatedly weighed 4 times. The
zhannawk [14.2K]

Answer:

(0.9464,1.034)

Step-by-step explanation:

First find the mean μ  of all values as;

(0.95+1.02+ 1.01+ 0.98 ) /4 =0.99

μ=0.99

Find the standard deviation as;

-For each value subtract the mean and square the results

0.95-0.99 = -0.04 , -0.04² = 0.0016

1.02-0.99= 0.03, 0.03²=0.0009

1.01-0.99= 0.02, 0.02²= 0.0004

0.98-0.99 = -0.01, -0.01²=0.0001

Find mean of squared deviations as;

(0.0016+0.0009+0.0004+0.0001)/4 =0.00075 ----variance

Standard deviation = √0.00075 = 0.0274

δ = 0.0274

n=4

Thus n< 30 , confidence interval for μ = x ± t*δ/√n ---------(i)

Degree of freedom (df) = n-1 =4-1 =3

The t value for 95% confidence with df= 3 is t=3.182

Substituting the values in equation (i)

0.99 ± 3.182 * 0.0274/√4

0.99 ± 3.182 * 0.0274/2

0.99 ± 3.182 * 0.0137

0.99 ± 0.0436

(0.9464,1.034)

8 0
3 years ago
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