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Rom4ik [11]
3 years ago
9

Given the perimeter of a rectangle is 96 meter and the length is twice the width, find the dimensions. Solve algebraically.

Mathematics
2 answers:
barxatty [35]3 years ago
7 0
96 + 96
2(96x2) is the answer
Nitella [24]3 years ago
4 0
96/6=16

16+32+16+32=96

The length would be 32 while the width would be 16.
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