Given the perimeter of a rectangle is 96 meter and the length is twice the width, find the dimensions. Solve algebraically.

2 answers:

7 0

96 + 96
2(96x2) is the answer

4 0

96/6=16

16+32+16+32=96

The length would be 32 while the width would be 16.

You might be interested in

Bond [772]

Answer:

59 degrees, 44 plus 77 is 121, subtract from 180

4 0

2 years ago

olga55 [171]

Answer:

$\frac{12}{105}$

Step-by-step explanation:

$\frac{3}{5}x\frac{2}{7}x\frac{2}{3}$

3x2x2=12

5x7x3=105

$\frac{12}{105}$

6 0

2 years ago

stellarik [79]

Answer:it is 18

Step-by-step explanation:

You do 40=2x+4 then do 40-4 and get 36 then 36/2 is 18

3 0

3 years ago

Alchen [17]

6 0

3 years ago

Amiraneli [1.4K]

A=3,500×(1+0.03÷2)^(2×20)
A=6,349.06

5 0

3 years ago