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kondor19780726 [428]
3 years ago
9

T F All static local variables are initialized to −1 by default.

Computers and Technology
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

F

Explanation:

they are initialized to 0 by default.static variables are shared variables

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Select the correct line of missing code to create an output of "hello."
s2008m [1.1K]

Answer:

B

Explanation:

This feels like an error on the question issuer's part.

3 0
3 years ago
What is that tool that makes liquid metal? It is used for wires, Ik I might sound dumb but I'm rlly curious​
Alex_Xolod [135]

Answer:

A blow torch?

Explanation:

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3 years ago
Randy earn $22 per hour. This is an example of
ra1l [238]

Answer:

I am confused what the question is asking, but I am guessing what $22 per hour means? He earns $22 for every hour he works or does something.

So this hourly wage?  

Wage is the answer you are looking for.

8 0
3 years ago
What is the numeric range of a 16-bit twos complement value? A 16-bit excess notation value? A 16-bit unsigned binary value?
blagie [28]

Answer:

twos complement value is (-2^15 -1) -32768 to 32767.

excess notation value is -32768 to 32767.

unsigned binary value is (2^16) 0 to 65535

Explanation:

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Twos complement notation: As opposed to excess notation, a sign bit of 0 is used to represent the non-negative (+) sign and a 1 for the negative (-); again, zero is included in the non-negative set.

Unsigned Binary values: are binary values/bits that don't have signs

7 0
4 years ago
Determine the number of bytes necessary to store an uncompressed RGB color image of size 640 × 480 pixels using 8, 10, 12 and 14
dexar [7]

Answer:

For 8 bits / Color Channel: 921, 600 bytes.

For 10 bits / Color Channel: 1,152,000 bytes.

For 12 bits / Color Channel: 1,382,400 bytes.

For 14 bits / Color Channel : 1,612, 800 bytes.

Explanation:

Un uncompressed RGB color image of 640 pixels wide by 480 pixels height (VGA resolution) uses 3 samples of x bits fin order to represent the quantity of each primary color (red, green and blue) in a given pixel of the image.

So, if we use 8 bits/ sample, we can calculate the bytes needed to store a complete image as follows:

640*480*3*8 bits = 7, 372,800 bits. (1)

As, by definition, 1 byte= 8 bits, we have:

Nº of bytes = 7,372,800 / 8 = 921,600 bytes. (2)

In order to get the bytes needed to store the same image, using 10, 12 and 14 bits/ sample, all we need is replacing 8 by 10, 12 and 14 in (1), and then dividing by 8 as in (2).

Proceeding in this way we obtain:

640*480*3*10 = 9,216,000 bits ⇒    1,152,000 bytes.

640*480*3*12 = 11,059,200 bits ⇒   1,382,400 bytes.

640*480*3*14=   12,902,400 bits ⇒  1,612,800 bytes.

8 0
4 years ago
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