The area of a circular sector of central angle α (in radians) in a circle of radius r is given by
... A = (1/2)r²×(α - sin(α))
Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.
... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))
... A ≈ 16.07
Radii are in inches so the units of area will be in². The appropriate choice is
... 16.10 in²
_____
It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.
Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
I’m confused what we are suppose to do
Answer:
f(x)⁻¹ = (x - 11)²
Step-by-step explanation:
To find the inverse of the function, you need to (1) swap the places of the "x" and "y" variables and then (2) solve for "y". Remember, f(x) is another way of writing "y".
y = √x + 11 <----- Original equation
x = √y + 11 <----- Swap variables
x - 11 = √y <----- Subtract 11 from both sides
(x - 11)² = (√y)² <----- Square both sides
(x - 11)² = y <----- Simplify
Another way of writing the output of an inverse function is with f(x)⁻¹.
Answer:
3:45
Step-by-step explanation:
because if you add 2 to 1 it is 3 and that is 3pm and it says 2:00 and the 00 are the minutes minutes so you can add those in and it will be 45 so 3:45
