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3 years ago

15

Help.....................

1 answer:

Illusion [34]3 years ago

8 0

Answer:

<em><u>cube</u></em>

Step-by-step explanation:

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What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$

5 0

3 years ago

Helppppppppppppppppppppp

melisa1 [442]

Answer is 34 ft squared

3 0

3 years ago

Two-thirds of the sum of a number squared and 5 is fourteen

RideAnS [48]

Answer:

2/3( x^2 + 5 ) = 14 or 2/3x^2 - 32/3

Step-by-step explanation:

Part 1:

Two-thirds ( 2/3 )

of the ( (---) )

sum ( + )

of a number squared ( x^2 ) and 5 ( + 5 )

is fourteen ( = 14 )

Part 2 (Not super confident about):

2/3( x^2 + 5 ) = 14

2/3x^2 + 10/3 = 14

2/3x^2 - 32/3

Hopefully this helps!

Brainliest please?

7 0

2 years ago

F(x)=4x+5whsts the value of. F(-3). Is

MArishka [77]

Figure out the value

8 0

3 years ago

Read 2 more answers

From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°

Svetlanka [38]

Answer:

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

The height of the vertical cliff = h = 50 meters

The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

<u>Now, from figure</u>

Tan angle = $\dfrac{\textrm perpendicular}{\textrm base}$

I.e TanФ = $\dfrac{\textrm AB}{\textrm OA}$

Or, TanФ = $\dfrac{\textrm h}{\textrm x}$

Or, Tan 70° = $\dfrac{\textrm 50 meters}{\textrm x meters}$

Or, 2.74 = $\dfrac{\textrm 50}{\textrm x}$

∴ x = $\dfrac{\textrm 50}{\textrm 2.74}$

I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

5 0

3 years ago