All categories

2 years ago

If a ship has sufficient food to supply 600 passenger for 3 weeks how long would the food last for 800 passengers?

1 answer:

3 0

In the given problem the trick lies in the fact that the time upto which the food supply would last for 600 passengers is given in weeks and that is 3 weeks. First thing to do is convert the 3 weeks to number of days. Then it would be easy to find the number of days the same food supply would last if the number of passengers increases to 800.
Then
3 week = 21 days
Now
For 600 passengers in the ship the food supply will last for = 21 days
then
For 800 passengers in the ship the food supply will last for = (21/800) * 600
= (21/8) * 6
= 15.75 days
So the food supply for 800 passengers would last for 15.75 days

You might be interested in

Select all the expressions that are equivalent to 4-3.

Leviafan [203]

Answer:

See below.

Step-by-step explanation:

4*-3

A) -12

C) 2*-6

-hope it helps

3 0

2 years ago

would a field with a width 75 yards and an area of 7500 square yards be within FIFA regulation?why or why not.

worty [1.4K]

Im not really sure but i thinki think it is

4 0

3 years ago

34. A MasterCard statement shows a balance of $510 at 13.9% compounded monthly. What monthly payment will pay off this debt in 1

bixtya [17]

Answer:

The monthly payment is $35.10.

Step-by-step explanation:

p = 510

r = $13.9/12/100=0.011583$

n = $12+4=16$

The EMI formula is :

$\frac{p\times r\times(1+r)^{n} }{(1+r)^{n}-1 }$

Now putting the values in formula we get;

$\frac{510\times0.011583\times(1+0.011583)^{16} }{(1+0.011583)^{16}-1 }$

=> $\frac{510\times0.011583\times(1.011583)^{16} }{(1.011583)^{16}-1 }$

= $35.10

Therefore, the monthly payment is $35.10.

8 0

3 years ago

suppose X and Y are independent random variables, both with normal distributions. If X has a mean of 45 with a standard deviatio

djyliett [7]

Answer:

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu_X = 45, \sigma_X = 4, \mu_Y = 35, \sigma_Y = 3$

What is the probability that a randomly generated value of X is greater than a randomly generated value of Y

This means that the subtraction of X by Y has to be positive.

When we subtract two normal variables, the mean is the subtraction of their means, and the standard deviation is the square root of the sum of their variances. So

$\mu = \mu_X - \mu_Y = 45 - 35 = 0$