Answer:
41x² - 27x + 27
Step-by-step explanation:
Perimeter of Rectangle:
= 2(20x²-12x+4) + 2(5x²-5x+15)
= 40x²-24x+8 + 10x²-10x+30
= 50x²-34x+38
Perimeter of Triangle:
= 6x²+6x+3x+3+3x²-2x+8
= 9x²+7x+11
Difference:
(50x²-9x²)+(-34x+7x)+(38-11)
= 41x² - 27x + 27
The answer is : Sn = S(n-1) + n
f(x) > 0 - I and II quadrant
f(x) < 0 - III and IV quadrant
Look at the picture.
A. F(x) < 0 on the interval x < 0. TRUE
B. F (x) > 0 on the interval x <0. FALSE
C. F (x) < 0 on the interval 0 < x < 1. TRUE
D. F (x) > 0 on the interval 0 < x < 1. FALSE
E. F (x) < 0 on the interval 1 < x < 3. FALSE
F. F (x) > 0 on the interval 1 < x < 3. TRUE
G. F (x) < 0 on the interval x > 3. TRUE
H. F (x) > 0 on the interval x > 3. FALSE