All categories

3 years ago

HELP ME PLEASE PLEASE IM BEGGING

Mathematics

1 answer:

suter [353]3 years ago

6 0

Answer:

FALSE, (2, 9) is not a solution to the set of inequalities given.

Step-by-step explanation:

Simply replace x by 2 and y by 9 in the inequalities and see if the inequality is true or not:

irst inequality:

$y\geq 4x\\9\geq 4\,(2)\\9\geq 8$

so thi inequality is verified as true since 9 is larger or equal than 8

Now the second inequality:

$y$

This is FALSE since 9 is larger than 4 (not smaller)

Therefore the answer to the question is FALSE, (2, 9) is not a solution to the set of inequalities given.

You might be interested in

Which two numbers add up to 7 and multiply to 13

liubo4ka [24]

Its a trick question nothing multiplies to get 13 except by 1 and 13

6 0

4 years ago

Read 2 more answers

What is the rotational symmetry of a rectangle

Fudgin [204]

Order 2 rectangle has only 2

6 0

4 years ago

<img src="https://tex.z-dn.net/?f=%28%20-%208x%7D%5E%7B2%7D%20%20-%205x%20-%206%29%20%2B%20%28%20-%20x%20%7B%20%7D%5E%7B2%7D%20-

Jlenok [28]

Hello! I hope this helps! <33

Answer:

-9x^2-6x-1

Step-by-step explanation:

1.) Remove parantheses

-8x^2-5x-6-x^2-x+5

2.) Group like terms

8x^2-x^2-5x-x-6+5

3.) Add similar elements

-9x^2-5x-x-6+5

4.) Add similar elements

-9x^2-6x-6+5

Answer = -9x^2-6x-6+5

Have a nice day! ;)

8 0

3 years ago

Given the second order homogeneous constant coefficient equation y′′−4y′−12y=0 1) the characteristic polynomial ar2+br+c is r^2-

Vitek1552 [10]

Answer:

The initial value problem $y(x) = 4 e^{-2x} -3 e^{6 x}$

Step-by-step explanation:

Step1:-

a) Given second order homogenous constant co-efficient equation

$y^{ll} - 4y^{l}-12y=0$

Given equation in the operator form is $(D^{2} -4D-12)y=0$

Step 2:-

b) Let f(D) = $(D^{2} -4D-12)y$

Then the auxiliary equation is $(m^{2} -4m-12)=0$

Find the factors of the auxiliary equation is

$m^{2} -6m+2m-12=0$

m(m-6) + 2(m-6) =0

m+2 =0 and m-6=0

m=-2 and m=6

The roots are real and different

The general solution $y = c_{1} e^{-m_{1} x} + c_{2} e^{m_{2} x}$

the roots are $m_{1} = -2 and m_{2} = 6$

The general solution of given differential equation is

$y = c_{1} e^{-2x} + c_{2} e^{6 x}$

Step 3:-

C) Given initial conditions are y(0) =1 and y1 (0) =-26

The general solution of given differential equation is

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$ .....(1)

substitute x =0 and y(0) =1

$y(0) = c_{1} e^{0} + c_{2} e^{0}$

$1 = c_{1} + c_{2}$ .........(2)

Differentiating equation (1) with respective to 'x'

$y^l(x) = -2c_{1} e^{-2x} + 6c_{2} e^{6 x}$

substitute x= o and y1 (0) =-26

$-26 = -2c_{1} e^{0} + 6c_{2} e^{0}$

$-2c_{1} + 6c_{2} = -26$ .............(3)

solving (2) and (3) by using substitution method

$substitute c_{2} =1- c_{1}$ in equation (3)

$-2c_{1} + 6(1-c_{1}) = -26$

on simplification , we get

$-2c_{1} + 6(1)-6c_{1}) = -26$

$-8c_{1} = -32$

dividing by'8' we get $c_{1} =4$

substitute $c_{1} =4$ in equation $1 = c_{1} + c_{2}$

so $c_{2} = 1-4 = -3$

now substitute $c_{1} =4 and c_{2} =-3$ in general solution

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$

$y(x) = 4 e^{-2x} -3 e^{6 x}$

now the initial value problem

$y(x) = 4 e^{-2x} -3 e^{6 x}$

7 0

4 years ago

Money savers bank offers a savings account that earns 6% interest compounded continuously. If Manuel deposits $2200, how much wi

telo118 [61]

Answer:

2633.88

Step-by-step explanation:

Pe^rt

2200*e^.06*3

7 0

2 years ago