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Murljashka [212]
3 years ago
9

Given the picture, what is the length of AC? A) 4.5 B) 5 C) 7.5 D) 8

Mathematics
1 answer:
drek231 [11]3 years ago
7 0

we know that

triangles BCD and ACE are similar

so, their ratios of sides must be equal

Calculation of y:

\frac{BC}{AC}=\frac{CD}{CE}

we can see that

AC=AB+BC

AC=y+3

CE=CD+DE

CE=4+6

CE=10

now, we can plug values

\frac{3}{y+3}=\frac{4}{10}

now, we can solve for y

3*10=4*(y+3)

30=4y+12

30-12=4y+12-12

18=4y

y=4.5

Calculation of AC:

we know that

AC=y+3

we can plug y

and we get

AC=4.5+3

AC=7.5...................Answer


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oee [108]

Answer:

Z-score = 1.18

Step-by-step explanation:

The z-score measures how many standard deviations from the mean a data is

Therefore the z score is the quotient between the difference between a value and the mean and the standard deviation

Z =\frac{X-\mu}{\sigma}

Where

μ is the mean, x is a data of the population and \sigma is the standard deviation

In this case

\mu =101\\\\\sigma = 3.4\\\\X = 105

Then the z-score is

Z = \frac{105-101}{3.4}\\\\Z = 1.18

4 0
4 years ago
josh , James and John share sweets in ratio 1:2:4 . Josh has 9 sweets less than John . how many sweets does John have ?​
disa [49]

Answer:

12

Step-by-step explanation:

1:2:4

let josh=1x

james=2x

john=4x

josh has nine sweets less than john

4x-1x=9

3x=9

x=3

john's sweet=4x

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3 0
2 years ago
For brainiest:):):):):):):)
andrew-mc [135]

Answer:

15 = 0.025

16= 3 years

Step-by-step explanation:

15.

I=prt

15= (200)(r)(3)

200(3) = 600r

15 divided by 600r = 40 (0.025)

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16.

I=prt

t= \frac{I}{Ixp} \\t= \frac{90}{0.05x600} \\t= 3

t= 3 years

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3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

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Step-by-step explanation:

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