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vitfil [10]
3 years ago
7

In ΔNOP, the measure of ∠P=90°, the measure of ∠O=17°, and OP = 8.6 feet. Find the length of PN to the nearest tenth of a foot.

Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0

The length of PN is 2.63 feet

<u>Explanation:</u>

<u />

Given:

∠P=90°,

∠O=17°,

OP = 8.6 feet

PN = ?

The given triangle is a right angle triangle as one angle is 90°

We know:

tan \alpha = \frac{perpendicular}{base}

tan(17^o) = \frac{PN}{OP} \\\\0.3057 = \frac{PN}{8.6} \\\\PN = 0.3057 X 8.6 feet\\\\PN = 2.63 feet

Therefore, the length of PN is 2.63 feet

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3 + 6² = 3 + 36 = 39

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