Question

In ΔNOP, the measure of ∠P=90°, the measure of ∠O=17°, and OP = 8.6 feet. Find the length of PN to the nearest tenth of a foot.

Answer 1

The length of PN is 2.63 feet

Explanation:

Given:

∠P=90°,

∠O=17°,

OP = 8.6 feet

PN = ?

The given triangle is a right angle triangle as one angle is 90°

We know:

$tan \alpha = \frac{perpendicular}{base}$

$tan(17^o) = \frac{PN}{OP} \\\\0.3057 = \frac{PN}{8.6} \\\\PN = 0.3057 X 8.6 feet\\\\PN = 2.63 feet$

Therefore, the length of PN is 2.63 feet