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Nezavi [6.7K]
3 years ago
12

If angle a=11* what does angle be equal

Mathematics
2 answers:
kap26 [50]3 years ago
8 0

Answer: Add a picture, more info is needed to answer.

olya-2409 [2.1K]3 years ago
4 0
What type of shape is it, are any other angles given?
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X + y = 6<br> 2x + y = 4<br> Solve the system of equations.
Debora [2.8K]
(X,Y) = (-2,8) this the answer
8 0
3 years ago
Read 2 more answers
Miguel conducts a survey of 750 college students to see how many of them have a part-time job. His results show that 500 of the
4vir4ik [10]

Answer:

B. 700 put of 1100

Step-by-step explanation:

Mark me as brainliest if this helps!

5 0
3 years ago
A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
Please help me!!! I'm lost tap the attachment​
BabaBlast [244]

Answer:

Below.

Step-by-step explanation:

I'll do number 20, 21, 22 for you.

20.  It is ±1, ±2, ±4, ±8.

21.   Reflected over the x-axis and down 4.

22. Common ratio = 25/5 = 5.

23.  Imaginary roots occur in pairs so there is also a root -5i.

The answer is c.

19. Option (a).

This is a translation of 4 to the left ( due to the (x + 4).

3 0
3 years ago
Jerome has 1/4 of the group's video games at his house. Mario has 2/5 of the group's video games at his house. What fraction of
VikaD [51]
5/20 for Jerome and 8/20 for Mario. combined 13/20

3 0
3 years ago
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