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snow_tiger [21]
2 years ago
14

Answer all please, thank you :)

Mathematics
2 answers:
Naddik [55]2 years ago
8 0

Answer:

1.70

2. 55

3.70

Step-by-step explanation:

prisoha [69]2 years ago
6 0

The angles in a triangle add up to 180 degrees.  That's the same sum as a linear pair, which we get when two lines cross.

1. 180 - 65 - 45 = 70

Answer: 70°

2. 180 - 90 - 35 = 55

Answer: 55°

3. 180 - 120 = 180 - 50 - x

x = 70

Answer: 70°

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She can travel 3000 miles
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3 years ago
Find the area of each sector. Omg please help due in 5 min!!
mr Goodwill [35]
The answer is C (289pi/6 mi2)
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3 years ago
A Martian couple has children until they have 2 males (sexes of children are independent). Compute the expected number of childr
Ne4ueva [31]

Answer:

a) 6

b) 4

c) 3

Step-by-step explanation:

Let p be the probability of having a female Martian, and of course, 1-p the probability of having a male Martian.

To compute the expected total number of trials before 2 males are born, imagine an experiment simulating the fact that 2 males are born is performed n times.

Let ak be the number of trials performed until 2 males are born in experiment k. That is,

a1= number of trials performed until 2 males are born in experiment 1

a2= number of trials performed until 2 males are born in experiment 2

and so on.

If a1 + a2 + … + an = N

we would expect Np females.  

Since the experiment was performed n times, there 2n males (recall that the experiment stops when 2 males are born).

So we would expect 2n = N(1-p), or

N/n = 2/(1-p)

But N/n is the average number of trials per experiment, that is, the expectation.

<em>We have then that the expected number of trials before 2 males are born is 2/(1-p) where p is the probability of having a female. </em>

a)

Here we have the probability of having a male is half as likely as females. So

1-p = p/2 hence p=2/3

The expected number of trials would be

2/(1-2/3) = 2/(1/3) =6

This means <em>the couple would have 6 children</em>: 4 females (the first 4 trials) and 2 males (the last 2 trials).

b)

Here the probability of having a female = probability of having a male = 1/2

The expected number of trials would be

2/(1/2) = 4

This means<em> the couple would have 4 children</em>: 2 females (the first 2 trials) and 2 males (the last 2 trials).

c)

Here, 1-p = 2p so p=1/3

The expected number of trials would be

2/(1-1/3) = 2/(2/3) = 6/2 =3

This means<em> the couple would have 3 children</em>: 1 female (the first trial) and 2 males (the last 2 trials).

5 0
3 years ago
Convert 0.865 from Base 10 to Base 2.8 and 16.​
svetlana [45]

Answer:

Don't know

Step-by-step explanation:

can't help u in this

sorry

I am from India what about you I think Canada because I choose in states Canada

3 0
2 years ago
A community center is trying to raise $1680 to purchase exercise equipment. The center is hopping to receive equal contributions
goblinko [34]

Answer:

x = 1680 / N, where N is the number of people and x the amount each person has to give for equal contribution. So for N = 10 ==> x = 168.

Step-by-step explanation:

8 0
3 years ago
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