It would be an average of about 8.00 (7.99 to be somewhat exact). You get this by dividing the total amount by 200, the dividing that by 363.
Are you looking for the percentage? If you are, then you just have to find 8/9, which is about 0.89, or 89%.
Answer:
386m/s is the answer to your question
Answer:
Yes, I can reject the null hypothesis with 95% confidence.
Step-by-step explanation:
Critical value t(63) = 1.99
p-value = 0.03
Confidence level (C) = 95% = 0.95
Significance level = 1 - C = 1 - 0.95 = 0.05
Conclusion:
Reject the null hypothesis because the p-value 0.03 is less than the significance level 0.05.