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VLD [36.1K]
3 years ago
7

Find f(g(x)) and g(f(x)) and determine whether each pair of functions f and g are inverses of each other (pls include work and a

simple how-to)
1. f(x)
4x and g(x) = x/4
Mathematics
2 answers:
Elena-2011 [213]3 years ago
6 0

Answer:

  • Yes

Step-by-step explanation:

<u>Given:</u>

  • f(x) = 4x
  • g(x) = x/4

<u>Find the following:</u>

  • f(g(x)) = 4*g(x) = 4*x/4 = x
  • g(f(x)) = f(x)/4 = 4x/4 = x

Since f(g(x)) = g(f(x)) = x, the functions are inverses of each other.

seropon [69]3 years ago
4 0
  • f(x)=4x
  • g(x)=x/4

\\ \sf\longmapsto f(g(x))=4(x/4)=x

\\ \sf\longmapsto g(f(x))=4x/4=x

  • f(x) and g(x) are inverse of each other
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(x+4)(x-3)

Step-by-step explanation:

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The length and width of a rectangle are ( 2x -5) and ( 3 x +4) What is the Perimeter?
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Answer:

\fbox{ \sf{Perimeter \: of \: a \: rectangle = 10x - 2}}

Step-by-step explanation:

\star{ \sf{ \:  \: Length \: of \: a \: rectangle ( l )  = (2x - 5) }}

\star{ \sf{ \: Width \: of \:  a \: rectangle ( w ) = (3x + 4)}}

\star{ \sf{ \:  \: Perimeter \: of \: a \: rectangle =  ?}}

\boxed{ \bold{  \sf{Perimeter \: of \: a \: rectangle = 2(l + w)}}}

\hookrightarrow{ \sf{Perimeter \: of \: a \: rectangle = 2(2x - 5 + 3x + 4)}}

\text{Step \: 1 : \: Collect \: like \: term}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base}

\hookrightarrow{ \sf{2(2x  + 3x - 5 + 4)}}

\hookrightarrow{ \sf{2(5x - 5 + 4)}}

\text{Step \: 2  \: :  \: Subtract \: 4 \: from \: 5}

\text{Remember !\:  : the \: negative \: and \: positive \: integers \: are \: always \: subtracted \: but \: posses \: the \: sign \: of \: the \: bigger \: integer}

\hookrightarrow{ \sf{2(5x - 1)}}

\text{Step \: 3 \:  :  \: Distribute \: 2 \: through \: the \: parentheses}

\hookrightarrow{ \sf{2 \times 5x - 2 \times 1}}

\hookrightarrow{ \sf{10x - 2}}

\sf{∴ \: The \: perimeter \: of \: a \: rectangle = 10x - 2}

\text{Hope \: I \: helped !}

\text{Best \: regards ! }

~\text{TheAnimeGirl}

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3 years ago
In triangle ABC, it is given that angle A is 59 degrees and angle B is 53 degrees. The altitude from B to line AC is extended un
dsp73

Answer:

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Step-by-step explanation:

Call the point of intersection of BK and AC point P. Then line BK is a transversal to parallel lines AK and BC. Alternate interior angles AKB and PBC will be congruent.

We know that angle PCB is 68°, the difference between 180° and the sum of the two given angles in ΔABC:

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Since PB is an altitude, ∠CPB is a right angle. Then ∠PBC is the complement of ∠PCB, so is ...

  ∠PBC = 90° -68° = 22°

As we said, this is congruent to ∠AKB, so ...

  ∠AKB = 22°

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^ po polsku być powinno

Kto Polska?

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