Answer:
g(x) = x+1
Step-by-step explanation:
Informally, you can see that the function h(x) takes the root of a value that is 1 more than the value under the same radical in f(x). This suggests that adding 1 to x in f(x) will give you h(x). That is, ...
h(x) = f(x+1) = f(g(x))
so
g(x) = x+1
_____
More formally, you can apply the inverse of the function f(x) to the equation ...
h(x) = f(g(x))
f^-1(h(x)) = f^-1(f(g(x))) . . . inverse function applied
f^-1(h(x)) = g(x) . . . . . . . . . simplified
Now f^-1(x) can be found by solving for y in ...
x = f(y)
x = ∛(y+2) . . . . . . . . . definition of f(y)
x^3 = y+2 . . . . . . . . . cube both sides
x^3 -2 = y = f^-1(x) . . . subtract 2 from both sides
So, f^-1(h(x)) is ...
f^-1(h(x)) = g(x) = (∛(x+3))^3 -2 = x+3 -2
g(x) = x+1
Domain: 1 2 3 4 5 6 range: -1 0 1 2 3 6
For this case we have the following equation:
s = root (S.A / 6)
Substituting values we have:
For S.A = 180:
s = root (180/6)
s = root (30)
For S.A = 120:
s = root (120/6)
s = root (20)
s = root (4 * 5)
s = 2 * root (5)
Subtracting both values we have:
root (30) - 2 * root (5)
Answer:
root (30) - 2 * root (5)
option 2
<h3>
Answer:</h3>
- 6 large prints
- 12 small prints
<h3>
Step-by-step explanation:</h3>
<em>Numerical Reasoning</em>
Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...
... 2×$20 +45 = $85
To have revenue of at least $510, the studio must sell ...
... $510/$85 = 6
sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.
_____
<em>With an equation</em>
Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...
... 20·2x +45·x ≥ 510
... 85x ≥ 510
... x ≥ 510/85
... x ≥ 6
The studio needs to sell at least 6 large prints and 12 small prints.
Answer:
the answer is in the image if you have any questions let me know
Step-by-step explanation:
