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Reptile [31]
3 years ago
8

Maureen is taking an antibiotic. The table below shows the amount of antibiotic

Mathematics
1 answer:
Tems11 [23]3 years ago
7 0

Answer:

Answer: Maureen's body eliminated the bacteria faster then Ken's as if you multiply 150 times 0.976 you get a number larger then 90 so Ken would have eliminated 150 mg of antibiotics slower then Maureen ;We will use the equation for Ken on Maureen.

Step-by-step explanation:

f(t) =

So, in the first hour,

f(t) =  = 195.2 mg

In the second hour,

f(t) =  = 190.52 mg

In the third hour,

f(t) = = 186 mg

Now, comparing these values with Maureen's, we can see that she has a faster rate of 150,90,54 in the 1st, 2nd and 3rd hours respectively as compared to Ken.

So, we can conclude that Maureen's body eliminated the antibiotic faster than Ken's body.

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Y=-15x(12) I believe is the answer.
8 0
3 years ago
What is 7/8 minus 5/24 =?
marta [7]
I hope this helps you



7/8=7.3/8.3=21/24




7/8-5/24



21/24-5/24


16/24


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2/3
3 0
3 years ago
Nine students in Maddie's classroom are wearing red. There are
goblinko [34]

Answer:

She is correct because 30 percent of 30 is 9 or in other words if you multiply 30 by 30 percent you get 9.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help please bad please ​
Sergio [31]

Answer:

\displaystyle A .20

Step-by-step explanation:

<u>By </u><u>tangent</u><u> </u><u>theorem</u><u> </u>we acquire:

\displaystyle  x + 10 = 9 + 21

simplify addition:

\displaystyle  x + 10 = 30

cancel 10 from both sides:

\displaystyle  x = 20

hence,

our answer is A

4 0
3 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
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