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Reptile [31]
2 years ago
8

Maureen is taking an antibiotic. The table below shows the amount of antibiotic

Mathematics
1 answer:
Tems11 [23]2 years ago
7 0

Answer:

Answer: Maureen's body eliminated the bacteria faster then Ken's as if you multiply 150 times 0.976 you get a number larger then 90 so Ken would have eliminated 150 mg of antibiotics slower then Maureen ;We will use the equation for Ken on Maureen.

Step-by-step explanation:

f(t) =

So, in the first hour,

f(t) =  = 195.2 mg

In the second hour,

f(t) =  = 190.52 mg

In the third hour,

f(t) = = 186 mg

Now, comparing these values with Maureen's, we can see that she has a faster rate of 150,90,54 in the 1st, 2nd and 3rd hours respectively as compared to Ken.

So, we can conclude that Maureen's body eliminated the antibiotic faster than Ken's body.

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\frac{-9}{2}

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An automotive part manufacturer regularly makes shipments of 400 parts to merks auto repair. On average, 14 of the 400 parts are
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Answer:

no matter how many parts are in the shipment, 3.5% of the parts will be defective.

hope this helped, if so hit that thanks button ;D

Step-by-step explanation:


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2 years ago
If the student is a domain/inout and the hair color is the range/output how is these two set of relation not a function?
IRINA_888 [86]

Answer:

A function is a relation that maps inputs from a set called the domain, into outputs from a set called the range.

Such that each input can be mapped into only one output.

So for example, if we have a relation that maps the input 2 into two different values:

f(2) = 4

f(2) = 8

Then this is not a function.

In the case of the problem, we have a student as the input, and the hair color as the output.

So we will have something like:

f(student) = blond

And if this student decides to change his/her hair color to red?

Then the function becomes:

f(student) = red

So for the same input, we had two different outputs, which means that this is not a function.

We also could have the case where a given student has two colors (Californian for example)

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6 0
2 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

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2 years ago
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