Answer:
Adam and buford
Step-by-step explanation:
X^2 + y^2 = (3x^2 + 2y^2 - x)^2
2x + 2y f'(x) = 2(3x^2 + 2y^2 - x)(6x + 4y f'(x) - 1) = 36x^3 + 24x^2yf'(x) + 24xy^2 + 16y^3f'(x) - 4y^2 - 18x^2 - 8xyf'(x) + x
f'(x)(2y - 24x^2y - 16y^3 + 8xy) = 36x^3 + 24xy^2 - 4y^2 - 18x^2 - x
f'(x) = (36x^3 + 24xy^2 - 4y^2 - 18x^2 - x)/(2y - 24x^2y - 16y^3 + 8xy)
f'(0, 0.5) = -4(0.5)^2/(2(0.5) - 16(0.5)^3) = -1/(1 - 2) = -1/-1 = 1
Let the required equation be y = mx + c; where y = 0.5, m = 1, x = 0
0.5 = 1(0) + c = 0 + c
c = 0.5
Therefore, the tangent line at point (0, 0.5) is
y = x + 0.5
x=45
Step-by-step explanation:
x/5+7-7=16-7
5/1×x/5=9×5/1
x=45
Answer:
y=-x-1 or, y-8=-1(x+9)
Step-by-step explanation:
Parallel lines have the same slope. in your current equation you have a slope of <u>-1</u>. We can use this slope and your set of points in the point slope formula.
<u>y-y1=m(x-x1)</u>
(-9, 8)
x1 y1 m=-1
<u>y-8=-1(x+9)</u>
y-8=-1x-9
+8 +8
<u>y=-x-1</u>
Answer:
Line
Step-by-step explanation:
a linear function is a graph with a straight line that does not overlap and follows the form y=mx+b
