All categories

2 years ago

20. Solve 3(5x − 4) < 15x. All Real Numbers x>-4 x<4no solution

Mathematics

1 answer:

Natasha2012 [34]2 years ago

8 0

Answer:

No solution

Step-by-step explanation:

$3(5x - 4) < 15x \\ 15x - 12 < 15x \\ 15x - 15x < 12 \\ 0 < 12$

You might be interested in

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
\\
\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
\\
\\y' = \frac{3}{( -32 )}$

7 0

3 years ago

Can someone help me on this math problem ?

faltersainse [42]

Answer:

4/3

Step-by-step explanation:

Given two points, we can find the slope by using

m = (y2-y1)/(x2-x1)

= (20 - -16)/(7 - -20)

= (20+16)/(7+20)

= 36/27

=4/3

8 0

3 years ago

Can anyone help with this math problem?

Ne4ueva [31]

The answer is 8. You rewrite the fraction as 5.25.

6 0

3 years ago

Read 2 more answers

£150 is invested at 5% compound interest for 2 years. How much will be in the account at the end of the investment?

morpeh [17]

Answer:

165

Step-by-step explanation:

5% of 150 british pounds = 7.5 British pounds

2 years = 7.5 BS per year

7.5 + 7.5

= 15 british pounds

15 british pounds + 150 british pounds =

165 british pounds

7 0

2 years ago

Given that (in picture)...

GuDViN [60]

<h3>Answer: a = -3 and b = 5</h3>

=================================================

Work Shown:

Multiply top and bottom by $\sqrt{2}$ to rationalize the denominator

$\frac{10-\sqrt{18}}{\sqrt{2}}\\\\\frac{\sqrt{2}(10-\sqrt{18})}{\sqrt{2}*\sqrt{2}}\\\\\frac{\sqrt{2}*10-\sqrt{2}*\sqrt{18}}{\sqrt{2*2}}\\\\\frac{\sqrt{2}*10-\sqrt{2*18}}{\sqrt{4}}\\\\\frac{10\sqrt{2}-\sqrt{36}}{2}\\\\\frac{10\sqrt{2}-6}{2}\\\\\frac{-6+10\sqrt{2}}{2}\\\\\frac{2(-3+5\sqrt{2})}{2}\\\\-3+5\sqrt{2}\\\\$

We end up with something in the form $a+b\sqrt{2}$ where a = -3 and b = 5

7 0

2 years ago

20. Solve 3(5x − 4) < 15x. All Real Numbers x>-4 x<4no solution ​

20. Solve 3(5x − 4) < 15x. All Real Numbers x>-4 x<4no solution